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UGC NET JRF November 2020 Paper-2
November 28, 2023
P-NP
November 28, 2023
UGC NET JRF November 2020 Paper-2
November 28, 2023
P-NP
November 28, 2023

Question 13868 – UGC NET JRF November 2020 Paper-2

A non-pipeline system takes 50ns to process a task. The same task can be processed in a six-segment pipeline with a clock cycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks.

Correct Answer: B

Question 13 Explanation: 
Time required to execute 500 tasks without pipelining =500*50 ns=25000 ns
Time required to execute 500 tasks with 6-stage pipelining =(1*6*10)+(499*1*10)
=60+4990
=5050
A
6
B
4.95
C
5.7
D
5.5

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