Data-Communication
November 29, 2023Question 3734 – Data-Communication
November 29, 2023Data-Communication
| Question 16 |
Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is __________.
| 400 bps | |
| 800 bps | |
| 1600 bps | |
| 3200 bps |
Question 16 Explanation:
Given data,
— 4 channels are multiplexed using TDM
— Multiplex 1 byte per channel. So, total 4 bytes=4 channels.
— Each channel sends 100 bytes/sec
— Bit rate=?
Bit rate= 100 * 4 bytes(1 byte=8 bits)
= 100 * 4 *8 (we are converting into bits because we are finding bit rate)
= 3200 bps
— 4 channels are multiplexed using TDM
— Multiplex 1 byte per channel. So, total 4 bytes=4 channels.
— Each channel sends 100 bytes/sec
— Bit rate=?
Bit rate= 100 * 4 bytes(1 byte=8 bits)
= 100 * 4 *8 (we are converting into bits because we are finding bit rate)
= 3200 bps
Correct Answer: D
Question 16 Explanation:
Given data,
— 4 channels are multiplexed using TDM
— Multiplex 1 byte per channel. So, total 4 bytes=4 channels.
— Each channel sends 100 bytes/sec
— Bit rate=?
Bit rate= 100 * 4 bytes(1 byte=8 bits)
= 100 * 4 *8 (we are converting into bits because we are finding bit rate)
= 3200 bps
— 4 channels are multiplexed using TDM
— Multiplex 1 byte per channel. So, total 4 bytes=4 channels.
— Each channel sends 100 bytes/sec
— Bit rate=?
Bit rate= 100 * 4 bytes(1 byte=8 bits)
= 100 * 4 *8 (we are converting into bits because we are finding bit rate)
= 3200 bps