Question 5123 – UGC NET CS 2018 JUNE Paper-2
December 1, 2023Question 5125 – UGC NET CS 2018 JUNE Paper-2
December 1, 2023Question 5124 – UGC NET CS 2018 JUNE Paper-2
A graphic display system has a frame buffer that is 640 pixels wide, 480 pixels high and 1 bit of color depth. If the access time for each pixel on the average is 200 nanoseconds, then the refresh rate of this frame buffer is approximately :
Correct Answer: A
Question 8 Explanation:
Given data,
– Width (or) wide =640 pixels
– Height (or) High =480 pixels
– Color depth =1 bit/pixel
– Access time of each pixel on the average =200ns
– Refresh rate of frame buffer=?
Step-1: Graphic display system =640*480
=307200
Step-2: Memory required for Graphic display system =640*480*1
=307200
Step-3: Total screen access time = Memory required for Graphic display system * Access time of each pixel
= 307200*200 ns
= 61440000 ns
Step-4: Refresh rate of frame buffer per second=(10 -9 )/61440000
= 16.27604166 frames per second
[ Note: 10 -9 =1000000000 ]
– Width (or) wide =640 pixels
– Height (or) High =480 pixels
– Color depth =1 bit/pixel
– Access time of each pixel on the average =200ns
– Refresh rate of frame buffer=?
Step-1: Graphic display system =640*480
=307200
Step-2: Memory required for Graphic display system =640*480*1
=307200
Step-3: Total screen access time = Memory required for Graphic display system * Access time of each pixel
= 307200*200 ns
= 61440000 ns
Step-4: Refresh rate of frame buffer per second=(10 -9 )/61440000
= 16.27604166 frames per second
[ Note: 10 -9 =1000000000 ]
16 frames per second
19 frames per second
21 frames per second
23 frames per second
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