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Question 1011 –
December 6, 2023UGC NET CS 2016 July- paper-2
December 6, 2023GATE 2014 [Set-3]
| Question 38 |
An IP router with a Maximum Transmission Unit (MTU) of 1500 bytes has received an IP packet of size 4404 bytes with an IP header of length 20 bytes. The values of the relevant fields in the header of the third IP fragment generated by the router for this packet are
| MF bit: 0, Datagram Length: 1444; Offset: 370 | |
| MF bit: 1, Datagram Length: 1424; Offset: 185 | |
| MF bit: 1, Datagram Length: 1500; Offset: 370 | |
| MF bit: 0, Datagram Length: 1424; Offset: 2960 |
Question 38 Explanation:
Number of packet fragments = ⌈ (total size of packet)/(MTU) ⌉
So Datagram with data 4404 byte fragmented into 3 fragments.
So Datagram with data 4404 byte fragmented into 3 fragments.
Correct Answer: A
Question 38 Explanation:
Number of packet fragments = ⌈ (total size of packet)/(MTU) ⌉
So Datagram with data 4404 byte fragmented into 3 fragments.
So Datagram with data 4404 byte fragmented into 3 fragments.