Question 3389 – Communication
December 11, 2023Question 9994 – Digital-Logic-Design
December 11, 2023Question 10127 – Digital-Logic-Design
A ROM is sued to store the table for multiplication of two 8-bit unsigned integers. The size of ROM required is
Correct Answer: D
Question 11 Explanation:
When we multiply the two 8 bit numbers result will reach upto 16 bits. So we require 16 bits for each multiplication output.
No. of results possible = 28 × 28 = 216 = 64K
Then total size of ROM = 64K × 16
No. of results possible = 28 × 28 = 216 = 64K
Then total size of ROM = 64K × 16
256 × 16
64 K × 8
4 K × 16
64 K × 16
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