Programming
December 14, 2023GATE 2009
December 14, 2023GATE 2001
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Question 46
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Consider a machine with 64 MB physical memory and a 32-bit virtual address space. If the page size is 4 KB, what is the approximate size of the page table?
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16 MB
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8 MB
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2 MB
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24 MB
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Question 46 Explanation:
No. of entries in page table = 232/ 212 = 220
Frame size = 226 / 212 = 214
PT have to be stored in one frame so entry size must be 2 bytes, hence size of PT = 220 * 2 = 2 MB
Frame size = 226 / 212 = 214
PT have to be stored in one frame so entry size must be 2 bytes, hence size of PT = 220 * 2 = 2 MB
Correct Answer: C
Question 46 Explanation:
No. of entries in page table = 232/ 212 = 220
Frame size = 226 / 212 = 214
PT have to be stored in one frame so entry size must be 2 bytes, hence size of PT = 220 * 2 = 2 MB
Frame size = 226 / 212 = 214
PT have to be stored in one frame so entry size must be 2 bytes, hence size of PT = 220 * 2 = 2 MB