Programming
December 14, 2023GATE 2009
December 14, 2023GATE 2001
| Question 46 |
Consider a machine with 64 MB physical memory and a 32-bit virtual address space. If the page size is 4 KB, what is the approximate size of the page table?
| 16 MB | |
| 8 MB | |
| 2 MB | |
| 24 MB |
Question 46 Explanation:
No. of entries in page table = 232/ 212 = 220
Frame size = 226 / 212 = 214
PT have to be stored in one frame so entry size must be 2 bytes, hence size of PT = 220 * 2 = 2 MB
Frame size = 226 / 212 = 214
PT have to be stored in one frame so entry size must be 2 bytes, hence size of PT = 220 * 2 = 2 MB
Correct Answer: C
Question 46 Explanation:
No. of entries in page table = 232/ 212 = 220
Frame size = 226 / 212 = 214
PT have to be stored in one frame so entry size must be 2 bytes, hence size of PT = 220 * 2 = 2 MB
Frame size = 226 / 212 = 214
PT have to be stored in one frame so entry size must be 2 bytes, hence size of PT = 220 * 2 = 2 MB