Programming-for-Output-Problems
January 11, 2024Question 3150 – Papers-Articles-Workshop-Seminar-Conference-and-Symosium
January 11, 2024कंप्यूटर-नेटवर्क
| प्रश्न 50 |
संचार नेटवर्क में, L बिट्स की लंबाई वाला एक पैकेट p 1 की संभावना के साथ लिंक L1 या p 2 की संभावना के साथ लिंक L2 लेता है । लिंक L1 और L2 में क्रमशः बिट त्रुटि की संभावना b 1 और b 2 है। पैकेट के L1 या L2 के माध्यम से त्रुटि के बिना प्राप्त होने की संभावना है
| (1 – बी 1 ) एल पी 1 + (1 – बी 2 ) एल पी 2 | |
| [1 – (बी 1 + बी 2 ) एल ]पी 1 पी 2 | |
| (1 – बी 1 ) एल (1 – बी 2 ) एल पी 1 पी 2 | |
| 1 – (बी 1 एल पी 1 + बी 2 एल पी 2 ) |
Question 50 Explanation:
Probability of choosing link L1 = p1
Probability for no bit error for any single bit = (1 – b1)
Similarly, for link L2,
Probability of no bit error = (1 – b2)
Packet can go either through link L1 or L2, they are mutually exclusive events.
Probability packet will be received without any error = Probability of L1 being chosen and no errors in any of L bits + Probability of L2 being chosen and no error in any of the L bits
= (1 – b1)L p1 + (1 – b2)L p2
Hence, answer is option A.
Probability for no bit error for any single bit = (1 – b1)
Similarly, for link L2,
Probability of no bit error = (1 – b2)
Packet can go either through link L1 or L2, they are mutually exclusive events.
Probability packet will be received without any error = Probability of L1 being chosen and no errors in any of L bits + Probability of L2 being chosen and no error in any of the L bits
= (1 – b1)L p1 + (1 – b2)L p2
Hence, answer is option A.
Correct Answer: A
Question 50 Explanation:
Probability of choosing link L1 = p1
Probability for no bit error for any single bit = (1 – b1)
Similarly, for link L2,
Probability of no bit error = (1 – b2)
Packet can go either through link L1 or L2, they are mutually exclusive events.
Probability packet will be received without any error = Probability of L1 being chosen and no errors in any of L bits + Probability of L2 being chosen and no error in any of the L bits
= (1 – b1)L p1 + (1 – b2)L p2
Hence, answer is option A.
Probability for no bit error for any single bit = (1 – b1)
Similarly, for link L2,
Probability of no bit error = (1 – b2)
Packet can go either through link L1 or L2, they are mutually exclusive events.
Probability packet will be received without any error = Probability of L1 being chosen and no errors in any of L bits + Probability of L2 being chosen and no error in any of the L bits
= (1 – b1)L p1 + (1 – b2)L p2
Hence, answer is option A.