Question 9791 – Finite-Automata
February 12, 2024GATE 1994
February 12, 2024GATE 1994
| Question 4 |
Let A and B be any two arbitrary events, then, which one of the following is true?
| P(A∩B) = P(A)P(B) | |
| P(A∪B) = P(A) + P(B) | |
| P(A|B) = P(A∩B)P(B) | |
| P(A∪B) ≤ P(A) + P(B) |
Question 4 Explanation:
(A) Happens when A and B are independent.
(B) Happens when A and B are mutually exclusive.
(C) Not happens.
(D) P(A∪B) ≤ P(A) + P(B) is true because P(A∪B) = P(A) + P(B) – P(A∩B).
(B) Happens when A and B are mutually exclusive.
(C) Not happens.
(D) P(A∪B) ≤ P(A) + P(B) is true because P(A∪B) = P(A) + P(B) – P(A∩B).
Correct Answer: D
Question 4 Explanation:
(A) Happens when A and B are independent.
(B) Happens when A and B are mutually exclusive.
(C) Not happens.
(D) P(A∪B) ≤ P(A) + P(B) is true because P(A∪B) = P(A) + P(B) – P(A∩B).
(B) Happens when A and B are mutually exclusive.
(C) Not happens.
(D) P(A∪B) ≤ P(A) + P(B) is true because P(A∪B) = P(A) + P(B) – P(A∩B).