Data-Communication
March 6, 2024Data-Communication
March 6, 2024Computer-Networks
| Question 48 |
A company has a class C network address of 204.204.204.0. It wishes to have three subnets, one with 100 hosts and two with 50 hosts each. Which one of the following options represents a feasible set of subnet address/subnet mask pairs?
| 204.204.204.128/255.255.255.192 204.204.204.0/255.255.255.128 204.204.204.64/255.255.255.128 | |
| 204.204.204.0/255.255.255.192 204.204.204.192/255.255.255.128 204.204.204.64/255.255.255.128 | |
| 204.204.204.128/255.255.255.128 204.204.204.192/255.255.255.192 204.204.204.224/255.255.255.192 | |
| 204.204.204.128/255.255.255.128 204.204.204.64/255.255.255.192 204.204.204.0/255.255.255.192 |
Question 48 Explanation:
MSB in last 8 bits is in use to get subnet since it is class C IP.
10000000/128 (mask) – subnet id bit (1) (subnet 1)
01000000/192 (mask) – subnet id bit (01) (subnet 2)
0000000/192 (mask) – subnet id bit (00) (subnet 3)
10000000/128 (mask) – subnet id bit (1) (subnet 1)
01000000/192 (mask) – subnet id bit (01) (subnet 2)
0000000/192 (mask) – subnet id bit (00) (subnet 3)
Correct Answer: D
Question 48 Explanation:
MSB in last 8 bits is in use to get subnet since it is class C IP.
10000000/128 (mask) – subnet id bit (1) (subnet 1)
01000000/192 (mask) – subnet id bit (01) (subnet 2)
0000000/192 (mask) – subnet id bit (00) (subnet 3)
10000000/128 (mask) – subnet id bit (1) (subnet 1)
01000000/192 (mask) – subnet id bit (01) (subnet 2)
0000000/192 (mask) – subnet id bit (00) (subnet 3)