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Consider the following pseudo code. What is the total number of multiplications to be performed?
D = 2
for i = 1 to n do
for j = i to n do
for k = j + 1 to n do
D = D * 3
Correct Answer: C
Question 37 Explanation:
D = 2
for i = 1 to n do
for j = i to n do
for k = j + 1 to n do
D = D * 3;
Also you can try for smaller ‘n’.
for i = 1 to n do
for j = i to n do
for k = j + 1 to n do
D = D * 3;
Also you can try for smaller ‘n’.
Half of the product of the 3 consecutive integers.
One-third of the product of the 3 consecutive integers.
One-sixth of the product of the 3 consecutive integers.
None of the above.
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