Database-Management-System
March 27, 2024Question 11480 – APPSC-2012-DL CA
March 27, 2024APPSC-2012-DL CA
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Question 9
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If A and B are independent events then
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P(A∪B) = P(A) + P(B) + (A∩B)
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P(A∪B) = 0
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P(A∪B) = P(A) + P(B) – (A∩B)
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P(A∪B) = P(A) + P(B)
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None of the above
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Question 9 Explanation:
If A and B are independent events then
P(A∩B) = P(A)P(B)
So finally we can say that,
P(AUB) = P(A) + P(B) – P(A∩B)
= P(A) + P(B) – P(A)P(B)
P(A∩B) = P(A)P(B)
So finally we can say that,
P(AUB) = P(A) + P(B) – P(A∩B)
= P(A) + P(B) – P(A)P(B)
Correct Answer: E
Question 9 Explanation:
If A and B are independent events then
P(A∩B) = P(A)P(B)
So finally we can say that,
P(AUB) = P(A) + P(B) – P(A∩B)
= P(A) + P(B) – P(A)P(B)
P(A∩B) = P(A)P(B)
So finally we can say that,
P(AUB) = P(A) + P(B) – P(A∩B)
= P(A) + P(B) – P(A)P(B)