UGC NET CS 2006 June-Paper-2
May 6, 2024Access-Control-Methods
May 7, 2024Bit-Rate
| Question 11 |
For a channel of 3 KHz bandwidth and signal to noise ratio of 30 dB, the maximum data rate is :
| 3000 bps | |
| 6000 bps | |
| 15000 bps | |
| 30000 bps |
Question 11 Explanation:
→ Shannon Capacity (Noisy Channel) In presence of Gaussian band-limited white noise, Shannon-Hartley theorem gives the maximum data rate capacity.
C=B log2(1+S/N).
where S and N are the signal and noise power, respectively, at the output of the channel.
B=3 KHz = 3000 Hz
Signal to noise ratio=30 dB = 1000
C=3000*log2(1+1000)
=3000*9.967226258835992
= 29901.67 bps (Approximately 30000 bps)
C=B log2(1+S/N).
where S and N are the signal and noise power, respectively, at the output of the channel.
B=3 KHz = 3000 Hz
Signal to noise ratio=30 dB = 1000
C=3000*log2(1+1000)
=3000*9.967226258835992
= 29901.67 bps (Approximately 30000 bps)
Correct Answer: D
Question 11 Explanation:
→ Shannon Capacity (Noisy Channel) In presence of Gaussian band-limited white noise, Shannon-Hartley theorem gives the maximum data rate capacity.
C=B log2(1+S/N).
where S and N are the signal and noise power, respectively, at the output of the channel.
B=3 KHz = 3000 Hz
Signal to noise ratio=30 dB = 1000
C=3000*log2(1+1000)
=3000*9.967226258835992
= 29901.67 bps (Approximately 30000 bps)
C=B log2(1+S/N).
where S and N are the signal and noise power, respectively, at the output of the channel.
B=3 KHz = 3000 Hz
Signal to noise ratio=30 dB = 1000
C=3000*log2(1+1000)
=3000*9.967226258835992
= 29901.67 bps (Approximately 30000 bps)
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