###### Question 7116 – Computer-Networks

May 7, 2024###### Question 11871 – Computer-Networks

May 7, 2024# Question 7568 – Computer-Networks

Suppose a digitized voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it is assumed that each sample requires 8 bits?

Correct Answer: C

Question 711 Explanation:

t is required to sample the signal at twice the highest frequency (two samples per hertz).

Bit rate = current bandwidth * 2 * sample size.

Bit rate = 8 KHz * 2 * 8 bit.

= 8 K / sec * 2 * 8 bit.

= 128 kb / sec.

= 128 Kbps.

Bit rate = current bandwidth * 2 * sample size.

Bit rate = 8 KHz * 2 * 8 bit.

= 8 K / sec * 2 * 8 bit.

= 128 kb / sec.

= 128 Kbps.

32 kbps

64 kbps

128 kbps

256 kbps

Subscribe

Login

0 Comments