UGC NET CS 2014 June-paper-3
August 21, 2024UGC NET CS 2005 Dec-Paper-2
| Question 3 |
Let A and B be two arbitrary events, then :
| P(A∩B) = P(A) P(B) | |
| P(P∪B) = P(A) + P(B) | |
| P(A∪B) ≤ P(A) + P(B) | |
| P(A / B) = P(A∩B) + P(B) |
Question 3 Explanation:
Option-A is happens when A and B are independent.
Option-B is happens when A and B are mutually exclusive.
Option-C is not happens.
Option-D is P(A∪B) ≤ P(A) + P(B) is true because P(A∪B) = P(A) + P(B) – P(A∩B).
Option-B is happens when A and B are mutually exclusive.
Option-C is not happens.
Option-D is P(A∪B) ≤ P(A) + P(B) is true because P(A∪B) = P(A) + P(B) – P(A∩B).
Correct Answer: C
Question 3 Explanation:
Option-A is happens when A and B are independent.
Option-B is happens when A and B are mutually exclusive.
Option-C is not happens.
Option-D is P(A∪B) ≤ P(A) + P(B) is true because P(A∪B) = P(A) + P(B) – P(A∩B).
Option-B is happens when A and B are mutually exclusive.
Option-C is not happens.
Option-D is P(A∪B) ≤ P(A) + P(B) is true because P(A∪B) = P(A) + P(B) – P(A∩B).
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