IP-Address
September 7, 2024IP-Address
September 7, 2024Computer-Networks
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Question 465
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You need 500 subnets, each with about 100 usable host addresses per subnet. What network mass will you assign using a class B network address?
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255.255.255.252
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255.255.255.128
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255.255.255.0
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255.255.254.0
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Question 465 Explanation:
Explanation: We know that in class B addressing we have 16-bit network ID and !6-bits for host ID.
Since in question 500 subnets are required. Since 29 = 512, So we need to take 9 bits from host id part of class B addressing in order to provide 500 subnets and with remaining 7 bits of host id we can easily 100 usable hosts per subnet because 27 = 128.
Since we know that Subnet mask contains 1’s in subnet id part and the 0’s in host ID part. Hence subnet mask is:
11111111 . 11111111 . 11111111 . 10000000
In decimal form it can be represented as:
255 . 255 . 255 . 128
c
Since in question 500 subnets are required. Since 29 = 512, So we need to take 9 bits from host id part of class B addressing in order to provide 500 subnets and with remaining 7 bits of host id we can easily 100 usable hosts per subnet because 27 = 128.
Since we know that Subnet mask contains 1’s in subnet id part and the 0’s in host ID part. Hence subnet mask is:
11111111 . 11111111 . 11111111 . 10000000
In decimal form it can be represented as:
255 . 255 . 255 . 128
c
Correct Answer: B
Question 465 Explanation:
Explanation: We know that in class B addressing we have 16-bit network ID and !6-bits for host ID.
Since in question 500 subnets are required. Since 29 = 512, So we need to take 9 bits from host id part of class B addressing in order to provide 500 subnets and with remaining 7 bits of host id we can easily 100 usable hosts per subnet because 27 = 128.
Since we know that Subnet mask contains 1’s in subnet id part and the 0’s in host ID part. Hence subnet mask is:
11111111 . 11111111 . 11111111 . 10000000
In decimal form it can be represented as:
255 . 255 . 255 . 128
c
Since in question 500 subnets are required. Since 29 = 512, So we need to take 9 bits from host id part of class B addressing in order to provide 500 subnets and with remaining 7 bits of host id we can easily 100 usable hosts per subnet because 27 = 128.
Since we know that Subnet mask contains 1’s in subnet id part and the 0’s in host ID part. Hence subnet mask is:
11111111 . 11111111 . 11111111 . 10000000
In decimal form it can be represented as:
255 . 255 . 255 . 128
c
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