Computer-Networks
September 7, 2024IP-Address
September 7, 2024IP-Address
| Question 49 |
In a class B subnet, we know the IP address of one host and the mask as given below:
IP address: 125.134.112.66
Mask: 255.255.224.0
What is the first address(Network address)?
IP address: 125.134.112.66
Mask: 255.255.224.0
What is the first address(Network address)?
| 125.134.96.0 | |
| 125.134.112.0 | |
| 125.134.112.66 | |
| 125.134.0.0 |
Question 49 Explanation:
Given
IP address: 125.134.112.66
Subnet Mask: 255.255.224.0
IP address in binary Form = 01111101 10000110 01110000 01000010
Subnet Mask in binary Form = 11111111 11111111 11100000 00000000
Every IP address has Network id and Host id,
We will get Network id by doing bitwise -AND (&) operation with IP address and Subnet Mask
IP address: 125.134.112.66
Subnet Mask: 255.255.224.0
IP address in binary Form = 01111101 10000110 01110000 01000010
Subnet Mask in binary Form = 11111111 11111111 11100000 00000000
Every IP address has Network id and Host id,
We will get Network id by doing bitwise -AND (&) operation with IP address and Subnet Mask
Correct Answer: A
Question 49 Explanation:
Given
IP address: 125.134.112.66
Subnet Mask: 255.255.224.0
IP address in binary Form = 01111101 10000110 01110000 01000010
Subnet Mask in binary Form = 11111111 11111111 11100000 00000000
Every IP address has Network id and Host id,
We will get Network id by doing bitwise -AND (&) operation with IP address and Subnet Mask
IP address: 125.134.112.66
Subnet Mask: 255.255.224.0
IP address in binary Form = 01111101 10000110 01110000 01000010
Subnet Mask in binary Form = 11111111 11111111 11100000 00000000
Every IP address has Network id and Host id,
We will get Network id by doing bitwise -AND (&) operation with IP address and Subnet Mask
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