Functions
October 18, 2024LAN
October 18, 2024Switching
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Question 6
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In a packet switching network, if the message size is 48 bytes and each packet contains a header of 3 bytes. If 24 packets are required to transmit the message, the packet size is ________.
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2 bytes
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1 bytes
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4 bytes
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5 bytes
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Question 6 Explanation:
Given data,
— Message size=48 bytes
— Packet header=3 bytes
— 24 packets are carrying 48 bytes of data
— Packet size=?
Step-1: One packet carries maximum size is= Message size / Transmission message size
= 48 / 24
= 2 bytes
Step-2: Packet size= One packet carries maximum size + new packet header size
= 2 + 3
= 5 byte
— Message size=48 bytes
— Packet header=3 bytes
— 24 packets are carrying 48 bytes of data
— Packet size=?
Step-1: One packet carries maximum size is= Message size / Transmission message size
= 48 / 24
= 2 bytes
Step-2: Packet size= One packet carries maximum size + new packet header size
= 2 + 3
= 5 byte
Correct Answer: D
Question 6 Explanation:
Given data,
— Message size=48 bytes
— Packet header=3 bytes
— 24 packets are carrying 48 bytes of data
— Packet size=?
Step-1: One packet carries maximum size is= Message size / Transmission message size
= 48 / 24
= 2 bytes
Step-2: Packet size= One packet carries maximum size + new packet header size
= 2 + 3
= 5 byte
— Message size=48 bytes
— Packet header=3 bytes
— 24 packets are carrying 48 bytes of data
— Packet size=?
Step-1: One packet carries maximum size is= Message size / Transmission message size
= 48 / 24
= 2 bytes
Step-2: Packet size= One packet carries maximum size + new packet header size
= 2 + 3
= 5 byte