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NIC-NIELIT Scientist-B 2020
October 4, 2023
Engineering-Mathematics
October 4, 2023
NIC-NIELIT Scientist-B 2020
October 4, 2023
Engineering-Mathematics
October 4, 2023

UGC NET CS 2014 June-paper-3

Question 18
Consider a project with the following functional units :

Number of user inputs = 50

Number of user outputs = 40

Number of user enquiries = 35

Number of user files = 06

Number of external interfaces = 04

Assuming all complexity adjustment factors and weighing factors as average, the function points for the project will be

A
135
B
722
C
675
D
672
Question 18 Explanation: 

UFP= (50*4)+ ( 40*5)+(35*4)+(6*10)+(4*7)
UFP= 628
CAF = 0.65 + ( 0.01 * F )
F = 14 * scale
Since weighing factor is given as average. So scale value= 3
F= 42.
CAF = 1.07
FP= UFP* CAF
FP= 628*1.07
FP= 671.96
FP= 672(approximately)
Correct Answer: D
Question 18 Explanation: 

UFP= (50*4)+ ( 40*5)+(35*4)+(6*10)+(4*7)
UFP= 628
CAF = 0.65 + ( 0.01 * F )
F = 14 * scale
Since weighing factor is given as average. So scale value= 3
F= 42.
CAF = 1.07
FP= UFP* CAF
FP= 628*1.07
FP= 671.96
FP= 672(approximately)
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