NIC-NIELIT Scientist-B 2020
October 4, 2023Engineering-Mathematics
October 4, 2023Software-Engineering
| Question 135 |
Consider a project with the following functional units :
Number of user inputs = 50
Number of user outputs = 40
Number of user enquiries = 35
Number of user files = 06
Number of external interfaces = 04
Assuming all complexity adjustment factors and weighing factors as average, the function points for the project will be
| 135 | |
| 722 | |
| 675 | |
| 672 |
Question 135 Explanation:
UFP= (50*4)+ ( 40*5)+(35*4)+(6*10)+(4*7)
UFP= 628
CAF = 0.65 + ( 0.01 * F )
F = 14 * scale
Since weighing factor is given as average. So scale value= 3
F= 42.
CAF = 1.07
FP= UFP* CAF
FP= 628*1.07
FP= 671.96
FP= 672(approximately)
Correct Answer: D
Question 135 Explanation:
UFP= (50*4)+ ( 40*5)+(35*4)+(6*10)+(4*7)
UFP= 628
CAF = 0.65 + ( 0.01 * F )
F = 14 * scale
Since weighing factor is given as average. So scale value= 3
F= 42.
CAF = 1.07
FP= UFP* CAF
FP= 628*1.07
FP= 671.96
FP= 672(approximately)
Subscribe
Login
0 Comments