Question 10321 – Computer-Organization
April 21, 2024Question 8836 – GATE 2012
April 21, 2024Memory-Management
| Question 3 |
The capacity of a memory unit is defined by the number of words multiplied by the number of bits/word. How many separate address and data lines are needed for a memory of 4K × 16?
| 10 address, 16 data lines | |
| 11 address, 8 data lines | |
| 12 address, 16 data lines | |
| 12 address, 12 data lines |
Question 3 Explanation:
ROM memory size = 2m × n
m = no. of address lines
n = no. of data lines
Given, 4K × 16 = 212 × 16
Address lines = 12
Data lines = 16
m = no. of address lines
n = no. of data lines
Given, 4K × 16 = 212 × 16
Address lines = 12
Data lines = 16
Correct Answer: C
Question 3 Explanation:
ROM memory size = 2m × n
m = no. of address lines
n = no. of data lines
Given, 4K × 16 = 212 × 16
Address lines = 12
Data lines = 16
m = no. of address lines
n = no. of data lines
Given, 4K × 16 = 212 × 16
Address lines = 12
Data lines = 16
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