Computer-Networks
August 29, 2024Computer-Networks
August 29, 2024Computer-Networks
| Question 362 |
A noiseless 3 kHz channel transmits bits with binary level signals. What is the maximum data rate?
| 3 kbps | |
| 6 kbps | |
| 12 kbps | |
| 24 kbps |
Question 362 Explanation:
Bitrate = 2 * Bandwidth * log2(L)
where,
L = no. of signal levels
Since it is saying binary level signals, it means two level signals.
So,
L = 2
∴ Bitrate = 2 * 3 * 103 * log22
= 6 × 103 × 1 bps
= 6 kbps
where,
L = no. of signal levels
Since it is saying binary level signals, it means two level signals.
So,
L = 2
∴ Bitrate = 2 * 3 * 103 * log22
= 6 × 103 × 1 bps
= 6 kbps
Correct Answer: B
Question 362 Explanation:
Bitrate = 2 * Bandwidth * log2(L)
where,
L = no. of signal levels
Since it is saying binary level signals, it means two level signals.
So,
L = 2
∴ Bitrate = 2 * 3 * 103 * log22
= 6 × 103 × 1 bps
= 6 kbps
where,
L = no. of signal levels
Since it is saying binary level signals, it means two level signals.
So,
L = 2
∴ Bitrate = 2 * 3 * 103 * log22
= 6 × 103 × 1 bps
= 6 kbps
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