## STQC-NIELIT SC-B 2021

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*STQC-NIELIT SC-B 2021*. You scored %%SCORE%% out of %%TOTAL%%. Your performance has been rated as %%RATING%%
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Question 1 |

Q) Cloud, River, Mountain:

II | |

I | |

IV | |

III |

Question 1 Explanation:

Explanation:
cloud,river and mountain are three different things

Question 2 |

Q) Oxygen, Atmosphere, Nitrogen:

II | |

I | |

IV | |

III |

Question 2 Explanation:

Atmosphere consists of various gases. Oxygen and nitrogen are some of the gases present in the atmosphere.

Question 3 |

In each of the following questions, one number is wrong in the series. Find out the wrong number –
3, 5, 12, 39, 154, 772, 4634:

5 | |

3 | |

39 | |

154 |

Question 3 Explanation:

II number is 3*1+2 =5
III number is 5*2+2=12
IV number is 12*3+2=38
V number is 38*4+2=154
VI number is 154*5+2-772
So wrong number is 39

Question 4 |

701, 348, 173, 85, 41, 19, 8:

173 | |

41 | |

19 | |

348 |

Question 4 Explanation:

The wrong number is 348.
The correct sequence is 701,349,173,85,41,19,8
second number is 701- 352 = 349
third number is 349 - 176 = 173
fourth number is 173 - 88 = 85
fifth number is 85 - 44 = 41
sixth number is 41 - 22 = 19
and the seventh number is 19 - 11 = 8.
to get the next number in the sequence we are subtracting the sequence is 352,176,88,44,22,11. (which is every time we are dividing the number with 2)

Question 5 |

1, 9, 25, 49, 86, 121:

25 | |

121 | |

166 | |

86 |

Question 5 Explanation:

the correct sequence is 1,9,25,49,81,121= 12, 32 , 52, 72, 92, 112 ( which is squares of odd numbers)

Question 6 |

Rakesh is standing at a point. He walks 20 m towards the East and further 10m towards the South, then he walks 35m towards the West and further 5m towards the North, then he walks 15m towards the East. What is the straight distance in meters between his starting point and the point where he reached last?

0 | |

5 | |

10 | |

15 |

Question 6 Explanation:

https://solutionsadda.in/wp-content/uploads/2021/12/Zinc-1.1.jpg

Question 7 |

Directions (7 – 8): In the given questions below, a statement is given followed by two conclusions numbered I and II. You have to take the statement to be true. Read both the conclusions and decide which of the two or both following from the given statement. Give Answer:

(a)If only conclusion I follows (b) If only conclusion II follows

(b)If either I or II follows (d) If neither I nor II follows.

Q)A study of the planning commission reveals a boom in revenues. However, this has been of little avail owing to soaring expenditure. In the event, there has been a high dose of deficit financing, leading to marked rise in picket. Large financial outlays year after year had little impact on level of living.

I) A boom in revenues leads to rise in prices II) Large financial outlays should be avoided

(a)If only conclusion I follows (b) If only conclusion II follows

(b)If either I or II follows (d) If neither I nor II follows.

Q)A study of the planning commission reveals a boom in revenues. However, this has been of little avail owing to soaring expenditure. In the event, there has been a high dose of deficit financing, leading to marked rise in picket. Large financial outlays year after year had little impact on level of living.

I) A boom in revenues leads to rise in prices II) Large financial outlays should be avoided

If only conclusion I follows | |

If only conclusion II follows | |

If either I or II follows | |

If neither I nor II follows. |

Question 8 |

The top management has asked the four managers either to resign by tomorrow or face the order of service termination. Three of them have resigned till this very evening.

(I)The manager who did not resign yesterday will resign tomorrow (II)The management will terminate the service of one manager.

(I)The manager who did not resign yesterday will resign tomorrow (II)The management will terminate the service of one manager.

If only conclusion I follows | |

If only conclusion II follows | |

If either I or II follows | |

If neither I nor II follows |

Question 9 |

Who is the hockey player?

T | |

S | |

R | |

Q |

Question 9 Explanation:

P and S are unmarried ladies and do not participate in any game, so S is not a hockey player.
Q is the brother of R and is neither a chess player nor a hockey player. so Q is not a hockey player.
There is a married couple in which T is husband so R is wife. None of the ladies plays chess and football so R is a hockey player.

Question 10 |

Who is the wife of T?

Q | |

R | |

S | |

None of these |

Question 11 |

Which of the following is the correct group of ladies?

P, Q and R | |

Q, R and S | |

P. Q and S | |

P, R and S |

Question 11 Explanation:

P and S are unmarried ladies and R is the wife of T. So the correct group of ladies is P, R, and S.

Question 12 |

Who is the football player?

Q | |

R | |

S | |

T |

Question 12 Explanation:

R is a hockey player, S wont play any game, T is chess player, so Q is football player.

Question 13 |

Who is the chess player?

Q | |

R | |

S | |

T |

Question 14 |

Directions (1&18): Read the information given below and on the basis of the information, select the correct alternative for each question given after the information.

M and N are good at hockey and volleyball. O and M are good at hockey and baseball. P and N are good at cricket and volleyball. O, P and Q are good at football and basketball.

Q) Who is good at the largest number of games?

M and N are good at hockey and volleyball. O and M are good at hockey and baseball. P and N are good at cricket and volleyball. O, P and Q are good at football and basketball.

Q) Who is good at the largest number of games?

Q | |

P | |

O | |

N |

Question 15 |

M and N are good at hockey and volleyball. O and M are good at hockey and baseball. P and N are good at cricket and volleyball. O, P and Q are good at football and basketball.

Q) Who is good at cricket, baseball and volleyball?

Q) Who is good at cricket, baseball and volleyball?

Q | |

P | |

O | |

N |

Question 15 Explanation:

N is good at Volleyball, Cricket whereas O is only good at baseball according to the mentioned games in the question.

Question 16 |

Who is good at cricket, volleyball and hockey?

Q | |

P | |

O | |

N |

Question 17 |

Who among the following is good at four games?

Q | |

P | |

O | |

M |

Question 18 |

Who is good at baseball, hockey and volleyball?

Q | |

P | |

O | |

M |

Question 19 |

Read the information given below and on the basis of the information, select the correct alternative for each question given after the information.

(I) Six flats on a floor in two rows facing North and South are allotted to P, Q, R, S, T and U. (II) Q gets a north facing flat and is not next to S. (III) S and U get diagonally opposite flats. (IV) R next to U, gets a south facing flat and T gets a north facing flat. Whose flat is between Q and S?

(I) Six flats on a floor in two rows facing North and South are allotted to P, Q, R, S, T and U. (II) Q gets a north facing flat and is not next to S. (III) S and U get diagonally opposite flats. (IV) R next to U, gets a south facing flat and T gets a north facing flat. Whose flat is between Q and S?

T | |

U | |

R | |

P |

Question 20 |

The flats of which of the other pairs than SU, are diagonally opposite to each other?

PT | |

PQ | |

QR |

Question 20 Explanation:

Question 21 |

If the flats of T and P are interchanged, who’s flat will be next to that of U?

Q | |

T | |

P | |

R |

Question 21 Explanation:

https://solutionsadda.in/wp-content/uploads/2021/12/z1.2.jpg

Question 22 |

In a parallelogram ABCD, AP and BP are the angle bisectors of ∟DAB znc ∟ABC. Find ∟APB:

85 ^{0} | |

90 ^{0} | |

94 ^{0} | |

86 ^{0} |

Question 22 Explanation:

we know that, ∟DAB+ ∟ ABC=180
dividing by 2,
½ ∟ DAB+½ ∟ ABC= 180/2
∟ PAB + ∟PBA=90. ………(1 say)
hence, in triangle APB,
∟PAB +∟PBA + ∟APB=180. (Angle sum prop)
from 1,
angAPB+90= 180
ang APB=90

Question 23 |

A cuboid of dimension 24 cm × 9 cm × 8 cm is melted and smaller cubes of side 3 cm are formed. Find how many such cubes can be formed:

27 | |

64 | |

54 | |

32 |

Question 23 Explanation:

Volume of the cuboid : L*B*H = 24*9*8 = 1728 cm^3
Volume of the cube = (side)^3 = 3^3 = 27cm^3
Number of cubes possible = 1728 cm^3 / 27cm^3 = 64

Question 24 |

Instead of walking along two adjacent sides of a rectangular field, a boy took a short cut along the diagonal and saved a distance equal to half the longer side. Then, the ratio of the shorter side to the longer side is:

½ | |

2/3 | |

¼ | |

¾ |

Question 24 Explanation:

Let, Length = l say and breadth = b say.
According to given question we can write,
(l+b) - l2 + b2 = l/2
(l+b) -l/2 = l2 + b2
l + 2b = 2 l2 + b2 => l2+ 4b2 + 41lb = 4(l2 + b2)
b/l = 3/4

Question 25 |

In a fraction, the numerator is increased by 25% and the denominator is diminished by 10%. The fraction obtained is 5/9. The original fraction is:

2/5 | |

5/9 | |

3/5 | |

None of these |

Question 25 Explanation:

Let fraction is x/y
numerator increased by 25% then x will become 1.25x
denominator diminished by 10% then y will become 0.9x
From the given question we can write 1.25x0.9y= 59
xy= 25

Question 26 |

A factory employees skilled workers, unskilled, workers and clerks in the proportion 8 : 5 : 1 and the wages of a skilled worker, an unskilled worker and a clerk are in the ratio 5 : 2 : 3. When 20 unskilled workers are employed, the total daily wages of all (skilled workers, unskilled workers and clerks) amount to Rs. 318. The wages paid to each category of workers are:

Rs. 240, Rs. 60, Rs. 80 | |

Rs. 200, Rs. 90, Rs. 28 | |

Rs. 150, Rs. 108, Rs. 60 | |

Rs. 250, Rs. 50, Rs. 18 |

Question 26 Explanation:

Let us assume the common ratio of workers x and common ratio of wages is y.
So, 5x=20, or x= 4
So, skilled worker=8x4=32, unskilled worker= 20, clerks=4
Hence total wages=32x5y+20x2y+4x3y=212y
So, 212 y=318
or, y=1.5
So, daily wages of skilled workers = 5*1.5 = 7.5 Daily wages of unskilled worker=2*1.5 = 3
And daily wages of clerks =3*1.5= 4.5
Therefore, Wages paid to skilled workers = 7.5 * 32 = 240
wages paid to unskilled worker = 3*20 = 60
wages paid to clerks = 4.5*4 = 18

Question 27 |

½ log10 25 – 2 log10 3 + log10 18 equals:

18 | |

1 | |

log _{10}3 | |

None of these |

Question 27 Explanation:

Given that, ½ log10 25 – 2 log10 3 + log10 18 = ½ log10 5^2 – 2 log10 3 + log10 (9*2)
= log10 5 – log10 9 + log10 9 + log10 2
= log10 5 + log10 2
= log10 10
= 1

Question 28 |

In a mixture of 60L, the ratio of milk and water is 2 : 1. If the ratio of milk and water is to be 1 : 2, then the amount of water to be further added must be:

40 L | |

30 L | |

20 L | |

60 L |

Question 28 Explanation:

In a mixture of 60L, the ratio of milk and water is 2: 1, then milk is 40L and water is 20L.
if the ratio becomes 1:2, we need to add 60L of water then water becomes 80L.

Question 29 |

If x = p, y = q, then which of the following are p and q respectively for pair of equations 3x – 7y + 10 = 0 and y – 2x – 3 = 0:

– 1, 1 | |

1, 1 | |

1, 0 | |

0, 1 |

Question 29 Explanation:

Explanation: (-1,1) satisfies both the given equations.

Question 30 |

The students in a class are seated according to their marks in the previous examination. Once it so happens that four of these students get equal marks and therefore the same rank. To decide their seating arrangement, the teacher wants to write down all possible arrangements, one in each separate bit of paper, in order to choose one of these by lots. How many bits of paper are required?

9 | |

12 | |

15 | |

24 |

Question 30 Explanation:

We are given that four students got equal marks.
On one bit of paper, one arrangement of rank is to be written.
Let the students be named as A,B,C and D.
Now, A can be treated as having rank I in 4 ways.
B can be treated as having rank II in 3 ways.
C can be treated as having rank III in 2 ways.
D can be treated as having rank IV in 1 way.
Therefore, total number of bits of paper required for all arrangement
=4×3×2×1=24

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