Consider the following C program:

#include <stdio.h>
int main()
{
    int m = 10;
    int n, n1;
    n = ++m;
    n1 = m++;
    n--;
    --n1;
    n -= n1;
    printf("%d",n);
    return 0;
}

The output of the program is _______.

What will be the output of the following C program segment?

char inchar = 'A';
switch (inchar)
{
case 'A' :
    printf ("choice A n") ;
case 'B' :
    printf ("choice B ") ;
case 'C' :
case 'D' :
case 'E' :
default:
    printf ("No Choice") ;
}

Consider the following C program

int a, b, c = 0;
void prtFun (void);
int main ()
{
    static int a = 1; /* line 1 */
    prtFun();
    a += 1;
    prtFun();
    printf ( "n %d %d " , a, b) ;
}
  
void prtFun (void)
{
    static int a = 2; /* line 2 */
    int b = 1;
    a += ++b;
    printf (" n %d %d " , a, b);
}

What output will be generated by the given code segment?

Consider the following C program

int a, b, c = 0;
void prtFun (void);
int main ()
{
    static int a = 1; /* line 1 */
    prtFun();
    a += 1;
    prtFun();
    printf ( "n %d %d " , a, b) ;
}
  
void prtFun (void)
{
    static int a = 2; /* line 2 */
    int b = 1;
    a += ++b;
    printf (" n %d %d " , a, b);
}

What output will be generated by the given code segment if:

Line 1 is replaced by auto int a = 1;
Line 2 is replaced by register int a = 2;

What does the following fragment of C-program print?

char c[] = "GATE2011";
char *p =c;
printf("%s", p + p[3] - p[1]) ; 

Consider the following recursive C function that takes two arguments.

unsigned int foo(unsigned int n, unsigned int r)  {
       if(n>0) return ((n%r) + foo(n/r,r));
       else return 0;
}

What is the return value of the function foo when it is called as foo(513,2)?

Consider the following recursive C function that takes two arguments

unsigned int foo(unsigned int n, unsigned int r) {
  if (n  > 0) return (n%r +  foo (n/r, r ));
  else return 0;
}

What is the return value of the function foo when it is called as foo(345, 10) ?

What does the following program print?

#include
void f(int *p, int *q)
{
  p = q;
 *p = 2;
}
int i = 0, j = 1;
int main()
{
  f(&i, &j);
  printf("%d %d n", i, j);
  getchar();
  return 0;
}

What is the value printed by the following C program

#include
int f(int *a, int n)
{
  if(n <= 0) return 0;
  else if(*a % 2 == 0) return *a + f(a+1, n-1);
  else return *a - f(a+1, n-1);
}
  
int main()
{
  int a[] = {12, 7, 13, 4, 11, 6};
  printf("%d", f(a, 6));
  getchar();
  return 0;
}

Consider the program below:

#include 
int fun(int n, int *f_p)
{
    int t, f;
    if (n <= 1)
    {
        *f_p = 1;
        return 1;
    }
    t = fun(n- 1,f_p);
    f = t+ * f_p;
    *f_p = t;
    return f;
}
 
int main()
{
    int x = 15;
    printf (" %d n", fun(5, &x));
    return 0;
}

The value printed is:

Which combination of the integer variables x, y and z makes the variable a get the value 4 in the following expression?

     a = (x > y) ? ((x > z) ? x : z) : ((y > z) ? y : z) 

What is printed by the following C program?

int f(int x, int *py, int **ppz)           void main()
{                                               { 
  int y, z;                                      int c, *b, **a; 
  **ppz += 1; z = **ppz;                         c = 4; b = &c; a = &b;
  *py += 2; y = *py;                             printf("%d",f(c,b,a)); 
  x += 3;                                       }  
  return x + y + z;                                       
}  

Choose the correct option to fill ?1 and ?2 so that the program below prints an input string in reverse order. Assume that the input string is terminated by a newline character.

void reverse(void)
 {
  int c;
  if(?1)reverse();
  ?2
}
int main(){
  printf("Enter Text"); printf("n");
  reverse();printf("n") ;
}