RAM
Question 1 |
Which of the following is a random access (primary) memory?
Disk | |
Tape | |
ROM | |
None |
Question 1 Explanation:
Disk ,Tape ,ROM are all permanent storage memory.
Question 2 |
How many 64Kx1RAM chips are required to provide a memory of size 256K bytes?
8 | |
4 | |
32 | |
64 |
Question 2 Explanation:
Question 3 |
If each address space represents one byte of storage space, how many address lines are needed to access RAM chips arranged in a 4 x 6 array, where each chip is 8K x 4 bits ?
13 | |
15 | |
16 | |
17 |
Question 3 Explanation:
From the given data
Each chip size is = 8K x 4 bits = 23 x 210 x 22 == 215 bits = 212 bits
Given chip array = 6 x 4 = 24 ( 24=16 and 25=32)
So the number bits required for the total chips are 5 bits.
So, total number of bits required = 12 + 5 = 17 bits
Each chip size is = 8K x 4 bits = 23 x 210 x 22 == 215 bits = 212 bits
Given chip array = 6 x 4 = 24 ( 24=16 and 25=32)
So the number bits required for the total chips are 5 bits.
So, total number of bits required = 12 + 5 = 17 bits
There are 3 questions to complete.