Page-Replacement-algorithm
Question 1 |
The address sequence generated by tracing a particular program executing in a pure demand paging system with 100 records per page with 1 free main memory frame is recorded as follows. What is the number of page faults?
0100, 0200, 0430, 0499, 0510, 0530, 0560, 0120, 0220, 0240, 0260, 0320, 0370
13 | |
8 | |
7 | |
10 |
01, 02, 04, 04, 05, 05, 05, 01, 02, 02, 02, 03, 03.
Clearly 7 page faults.
Question 2 |
Which of the following page replacement algorithms suffers from Belady’s anamoly?
Optimal replacement | |
LRU | |
FIFO | |
Both (A) and (C) |
Question 3 |
Consider a virtual memory system with FIFO page replacement policy. For an arbitrary page access pattern, increasing the number of page frames in main memory will
always decrease the number of page faults | |
always increase the number of page faults | |
sometimes increase the number of page faults | |
never affect the number of page faults |
See Belady’s anomaly is the name given to the phenomenon where increasing the number of page frames results in an increase in the number of page faults for a given memory access pattern.
This phenomenon is commonly experienced in following page replacement algorithms:
First in first out (FIFO), Second chance algorithm, Random page replacement algorithm.
Question 4 |
The optimal page replacement algorithm will select the page that
Has not been used for the longest time in the past. | |
Will not be used for the longest time in the future. | |
Has been used least number of times. | |
Has been used most number of times. |
Question 5 |
Consider the following heap (figure) in which blank regions are not in use and hatched region are in use.
The sequence of requests for blocks of size 300, 25, 125, 50 can be satisfied if we use
either first fit or best fit policy (any one) | |
first fit but not best fit policy | |
best fit but first fit policy | |
None of the above |
So, request for 300 will be satisfied by 350 size block reducing the free size to 50.
Request for 25, satisfied by 125 size block, reducing it to 125.
Request for 125 satisfied by the 125 size block.
And request for 50 satisfied by 50 size block.
So, all requests can be satisfied.
In best fit strategy, a block request is satisfied by the smallest block in which can fit it. So, request for 300 will be satisfied by 350 size block reducing the free size to 50.
Request for 25, satisfied by 50 size block as its the smallest size that fits 25, reducing it to 25.
Request for 125, satisfied by 150 size block, reducing it to 25.
Now, request for 50 cannot be satisfied as the two 25 size blocks are not contiguous.
Question 6 |
A memory page containing a heavily used variable that was initialized very early and is in constant use is removed when
LRU page replacement algorithm is used | |
FIFO page replacement algorithm is used | |
LFU page replacement algorithm is used | |
None of the above |
In LRU which can eliminate (or) removed which is least recently used.
In LFU the frequency of the page is more. So it is in constant use so cannot be replaced.
Question 7 |
The following page addresses, in the given sequence, were generated by a program:
1 2 3 4 1 3 5 2 1 5 4 3 2 3
This program is run on a demand paged virtual memory system, with main memory size equal to 4 pages. Indicate the page references for which page faults occurs for the following page replacement algorithms.
(a) LRU (b) FIFO
Assume that the main memory is empty initially.
Theory Explanation. |
Question 8 |
Which page replacement policy sometimes leads to more page faults when size of memory is increased?
FIFO |
Question 9 |
Consider a fully associative cache with 8 cache blocks (numbered 0-7) and the following sequence of memory block requests:
4, 3, 25, 8, 19, 6, 25, 8, 16, 35, 45, 22, 8, 3, 16, 25, 7
If LRU replacement policy is used, which cache block will have memory block 7?
4 | |
5 | |
6 | |
7 |
4, 3, 25, 8, 19, 6, 16, 35
CPU array (first element being least recently used)
[4, 3, 19, 6, 25, 8, 16, 35]
So, 45 replaces 4.
45, 3, 25, 8, 19, 6, 16, 35 [3, 19, 6, 25, 8, 16, 35, 45]
Similarly, 22 replaces 3 to give,
45, 22, 25, 8, 19, 6, 16, 35 [19, 6, 25, 8, 16, 35, 45, 22]
8 hits in cache.
45, 22, 25, 8, 19, 6, 16, 35 [19, 6, 25, 16, 35, 45, 22, 8]
3 replaces 19,
45, 22, 25, 8, 3, 6, 16, 35 [6, 25, 16, 35, 45, 22, 8, 3]
16 and 25 hits in cache,
45, 22, 25, 8, 3, 6, 16, 35 [6, 35, 45, 22, 8, 3, 16, 25]
Finally, 7 replaces 6, which is in block 5.
Question 10 |
Assume that EA = (X)+ is the effective address equal to the contents of location X, with X incremented by one word length after the effective address is calculated; EA = −(X) is the effective address equal to the contents of location X, with X decremented by one word length before the effective address is calculated; EA = (X)− is the effective address equal to the contents of location X, with X decremented by one word length after the effective address is calculated. The format of the instruction is (opcode, source, destination), which means (destination ← source op destination). Using X as a stack pointer, which of the following instructions can pop the top two elements from the stack, perform the addition operation and push the result back to the stack.
6 and 1, 2, 3, 4 | |
7 and 1, 2, 4, 5 | |
8 and 1, 2, 4, 5 | |
9 and 1, 2, 3, 5 |
(Each page contains 16 bytes, so say for page0, it contains the virtual address 0-15)
0: page fault-1, pages in memory-0
4: page fault-1, pages in memory-0
8: page fault-1, pages in memory-0
20: page faults-2, pages in memory-0,1
24: page faults-2, pages in memory-0,1
36: page faults-3, pages in memory-0,1,2
44: page faults-3, pages in memory-0,1,2
12: page faults-3, pages in memory-1,2,0
68: page faults-4, pages in memory-1,2,0,4
72: page faults-4, pages in memory-1,2,0,4
80: page faults-5, pages in memory-2,0,4,5
84: page faults-5, pages in memory-2,0,4,5
28: page faults-6, pages in memory-0,4,5,1
32: page faults-7, pages in memory-4,5,1,2
88: page faults-7, pages in memory-4,1,2,5
92: page faults-7, pages in memory-4,1,2,5
Question 11 |
7, 2, 7, 3, 2, 5,3, 4, 6, 7, 7,1, 5, 6,1
the page fault rate, defined as the ratio of number of page faults to the number of memory accesses (rounded off to one decimal place) is_________.
0.60 |
Question 12 |
Consider the virtual page reference string
1, 2, 3, 2, 4, 1, 3, 2, 4, 1
On a demand paged virtual memory system running on a computer system that main memory size of 3 pages frames which are initially empty. Let LRU, FIFO and OPTIMAL denote the number of page faults under the corresponding page replacements policy. Then
OPTIMAL < LRU < FIFO | |
OPTIMAL < FIFO < LRU | |
OPTIMAL = LRU | |
OPTIMAL = FIFO |
No. of page faults with FIFO = 6
LRU:
No. of page faults with LRU = 9
Optimal:
No. of page faults with optimal = 5
∴ Optimal < FIFO < LRU
Question 13 |
Consider a main memory with five page frames and the following sequence of page references: 3, 8, 2, 3, 9, 1, 6, 3, 8, 9, 3, 6, 2, 1, 3. Which one of the following is true with respect to page replacement policies First-In-First Out (FIFO) and Least Recently Used (LRU)?
Both incur the same number of page faults
| |
FIFO incurs 2 more page faults than LRU | |
LRU incurs 2 more page faults than FIFO | |
FIFO incurs 1 more page faults than LRU |
∴ Number of page faults = 9
∴ Number of page faults = 9
Question 14 |
In which one of the following page replacement algorithms it is possible for the page fault rate to increase even when the number of allocated frames increases?
LRU (Least Recently Used) | |
OPT (Optimal Page Replacement) | |
MRU (Most Recently Used) | |
FIFO (First In First Out) |
In Belady’s anomaly is the phenomenon in which increasing the number of page frames results in an increase in the number of page faults for certain memory access patterns proves that it is possible to have more page faults when increasing the number of page frames while using the First in First Out (FIFO) page replacement algorithm.
In some situations, FIFO page replacement gives more page faults when increasing the number of page frames.
Question 15 |
Function Call | |
malloc Call | |
Page Fault | |
System Call |
Question 16 |
Consider a computer system with ten physical page frames. The system is provided with an access sequence (a1,a2,…,a20,a1,a2,…,a20), where each ai is a distinct virtual page number. The difference in the number of page faults between the last-in-first-out page replacement policy and the optimal page replacement policy is ___________.
1 | |
2 | |
3 | |
4 |
First we can consider LIFO (Last In First Out) →
a1 to a10 will result in page faults = 10 page faults,
Then a11 will replace a10 (last in is a10), a12 replace a11 and ...till a20 = 10 page faults and a20 will be top of stack and a9…a1 are remained as such.
Then a1 to a9 are already there.
So, 0 page faults from a1 to a9.
a10 will replace a20, a11 will replace a10 and so on = So 11 page faults.
So total faults will be 10+10+11 = 31.
Second Optimal Page Replacement Policy →
a1 to a10 = 10 page faults,
a11 will replace a10 because among a1 to a10, a10 will be used later, a12 will replace a11 and so on = 10 page faults.
a20 will be top of stack and a9…a1 are remained as such.
a1 to a9 = 0 page fault. a10 will replace a1 because it will not be used afterwards and so on, a10 to a19 will have 10 page faults.
So no page fault for a20.
Total = 10+ 10 +10 = 30.
So the difference between LIFO - Optimal = 1
Question 17 |
S1: Random page replacement algorithm (where a page chosen at random is replaced) suffers from Belady’s anomaly
S2: LRU page replacement algorithm suffers from Belady’s anomaly
Which of the following is CORRECT?
S1 is true, S2 is true | |
S1 is true, S2 is false | |
S1 is false, S2 is true | |
S1 is false, S2 is false |
Page replacement algorithm suffers from Belady's anomaly when it is not a stack algorithm.
S1: Random page replacement algorithm is not a stack algorithm. So, S1 is true.
S2: LRU is a stack algorithm. Therefore, it doesn't suffer from Belady's anomaly. S2 is false.