NTA UGC NET DEC-2022 Paper-1
August 10, 2023GATE 2022
August 11, 2023GATE 2023
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Question 14
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Consider the Deterministic Finite-state Automaton (DFA) A shown below. The DFA runs on the alphabet {0, 1}, and has the set of states {s, p, q, r}, with s being the start state and p being the only final state.
Which one of the following regular expressions correctly describes the language accepted by A?
Which one of the following regular expressions correctly describes the language accepted by A?
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1(0*11)*
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0(0 + 1)*
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1(0 + 11)*
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1(110*)*
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Question 14 Explanation:
From the given DFA diagram, it clearly shows that there is no outgoing edge from node “r” so Regular expression won’t start with “0” , Option -B eliminated.
Starting state is “s” and Final state is “p”.
There are two outgoing edges from the state “p”.
one edge from state “p” to itself with alphabet “0” and another from State “p” to “q” and “q” to “p” with alphabet “1”
So most suitable answer is option C
Starting state is “s” and Final state is “p”.
There are two outgoing edges from the state “p”.
one edge from state “p” to itself with alphabet “0” and another from State “p” to “q” and “q” to “p” with alphabet “1”
So most suitable answer is option C
Correct Answer: C
Question 14 Explanation:
From the given DFA diagram, it clearly shows that there is no outgoing edge from node “r” so Regular expression won’t start with “0” , Option -B eliminated.
Starting state is “s” and Final state is “p”.
There are two outgoing edges from the state “p”.
one edge from state “p” to itself with alphabet “0” and another from State “p” to “q” and “q” to “p” with alphabet “1”
So most suitable answer is option C
Starting state is “s” and Final state is “p”.
There are two outgoing edges from the state “p”.
one edge from state “p” to itself with alphabet “0” and another from State “p” to “q” and “q” to “p” with alphabet “1”
So most suitable answer is option C
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