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October 9, 2023###### Computer-Networks

October 9, 2023# Data-Structures

Question 9 |

Consider the array representation of a binary min-heap containing 1023 elements. The minimum number of comparisons required to find the maximum in the heap is _______.

511 |

Question 9 Explanation:

The binary heap contains 1023 elements.

When it performs minimum comparisons it will take Ceil(n/2)

n=1023

= Ceil(1023/2)

= 512

So, the maximum element is also part of n/2.

So, we have to subtract from the total elements

= 512-1

= 511

When it performs minimum comparisons it will take Ceil(n/2)

n=1023

= Ceil(1023/2)

= 512

So, the maximum element is also part of n/2.

So, we have to subtract from the total elements

= 512-1

= 511

Correct Answer: A

Question 9 Explanation:

The binary heap contains 1023 elements.

When it performs minimum comparisons it will take Ceil(n/2)

n=1023

= Ceil(1023/2)

= 512

So, the maximum element is also part of n/2.

So, we have to subtract from the total elements

= 512-1

= 511

When it performs minimum comparisons it will take Ceil(n/2)

n=1023

= Ceil(1023/2)

= 512

So, the maximum element is also part of n/2.

So, we have to subtract from the total elements

= 512-1

= 511

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