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October 9, 2023ComputerNetworks
October 9, 2023DataStructures
Question 9

Consider the array representation of a binary minheap containing 1023 elements. The minimum number of comparisons required to find the maximum in the heap is _______.
511

Question 9 Explanation:
The binary heap contains 1023 elements.
When it performs minimum comparisons it will take Ceil(n/2)
n=1023
= Ceil(1023/2)
= 512
So, the maximum element is also part of n/2.
So, we have to subtract from the total elements
= 5121
= 511
When it performs minimum comparisons it will take Ceil(n/2)
n=1023
= Ceil(1023/2)
= 512
So, the maximum element is also part of n/2.
So, we have to subtract from the total elements
= 5121
= 511
Correct Answer: A
Question 9 Explanation:
The binary heap contains 1023 elements.
When it performs minimum comparisons it will take Ceil(n/2)
n=1023
= Ceil(1023/2)
= 512
So, the maximum element is also part of n/2.
So, we have to subtract from the total elements
= 5121
= 511
When it performs minimum comparisons it will take Ceil(n/2)
n=1023
= Ceil(1023/2)
= 512
So, the maximum element is also part of n/2.
So, we have to subtract from the total elements
= 5121
= 511
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