UGC NET CS 2009 Dec-Paper-2
October 10, 2023UGC NET CS 2009 Dec-Paper-2
October 10, 2023UGC NET CS 2009 Dec-Paper-2
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Question 6
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The simplified form of the Boolean expression (X + Y + XY) (X + Z) is
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X + Y + ZX + Y
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XY – YZ
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X + YZ
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XZ + Y
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Question 6 Explanation:
Given boolean expression is (X+Y+XY) (X+Z)
Step-1: (X (1+Y)+Y) (X+Z) /* To take common as X */
Step-2: (X+Y) (X+Z) /* To take common as X */
Step-3: (X+YZ)
Step-1: (X (1+Y)+Y) (X+Z) /* To take common as X */
Step-2: (X+Y) (X+Z) /* To take common as X */
Step-3: (X+YZ)
Correct Answer: C
Question 6 Explanation:
Given boolean expression is (X+Y+XY) (X+Z)
Step-1: (X (1+Y)+Y) (X+Z) /* To take common as X */
Step-2: (X+Y) (X+Z) /* To take common as X */
Step-3: (X+YZ)
Step-1: (X (1+Y)+Y) (X+Z) /* To take common as X */
Step-2: (X+Y) (X+Z) /* To take common as X */
Step-3: (X+YZ)