Digital-Logic-Design
October 11, 2023Nielit Scientist-B CS 22-07-2017
October 11, 2023Computer-Organization
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Question 27
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A processor has 40 distinct instructions and 24 general purpose registers. A 32-bit instruction word has an opcode, two register operands and an immediate operand. The number of bits available for the immediate operand field is __________.
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16 bits
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17 bits
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18 bits
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19 bits
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Question 27 Explanation:
6 bits are needed for 40 distinct instructions (because, 25 < 40 < 26)
5 bits are needed for 24 general purpose registers (because, 24 < 24 < 25)
32-bit instruction word has an opcode (6 bit), two register operands (total 10 bits) and an immediate operand (x bits).
The number of bits available for the immediate operand field
⇒ x = 32 – (6 + 10) = 16 bits
5 bits are needed for 24 general purpose registers (because, 24 < 24 < 25)
32-bit instruction word has an opcode (6 bit), two register operands (total 10 bits) and an immediate operand (x bits).
The number of bits available for the immediate operand field
⇒ x = 32 – (6 + 10) = 16 bits
Correct Answer: A
Question 27 Explanation:
6 bits are needed for 40 distinct instructions (because, 25 < 40 < 26)
5 bits are needed for 24 general purpose registers (because, 24 < 24 < 25)
32-bit instruction word has an opcode (6 bit), two register operands (total 10 bits) and an immediate operand (x bits).
The number of bits available for the immediate operand field
⇒ x = 32 – (6 + 10) = 16 bits
5 bits are needed for 24 general purpose registers (because, 24 < 24 < 25)
32-bit instruction word has an opcode (6 bit), two register operands (total 10 bits) and an immediate operand (x bits).
The number of bits available for the immediate operand field
⇒ x = 32 – (6 + 10) = 16 bits
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