UGC NET CS 2014 Dec-Paper-2
October 12, 2023Algorithms
October 12, 2023UGC NET CS 2014 Dec-Paper-2
| Question 26 |
The period of a signal is 10 ms. What is its frequency in Hertz ?
| 10 | |
| 100 | |
| 1000 | |
| 10000 |
Question 26 Explanation:
First we change 10 ms to seconds, and then we calculate the frequency from the period (1 Hz = 10 −3 kHz).
10 ms=10*10 -3 s
=10 -2 s
Frequency(f)= 1/T
= 1/10 -2 Hz
=100 Hz
10 ms=10*10 -3 s
=10 -2 s
Frequency(f)= 1/T
= 1/10 -2 Hz
=100 Hz
Correct Answer: B
Question 26 Explanation:
First we change 10 ms to seconds, and then we calculate the frequency from the period (1 Hz = 10 −3 kHz).
10 ms=10*10 -3 s
=10 -2 s
Frequency(f)= 1/T
= 1/10 -2 Hz
=100 Hz
10 ms=10*10 -3 s
=10 -2 s
Frequency(f)= 1/T
= 1/10 -2 Hz
=100 Hz