UGC NET CS 2007 JunePaper2
October 13, 2023UGC NET CS 2007 JunePaper2
October 13, 2023UGC NET CS 2007 JunePaper2
Question 4

The regular expression given below describes :
r=(1+01)* (0+λ)
Set of all string not containing ‘11’


Set of all string not containing ‘00’


Set of all string containing ‘01’


Set of all string ending in ‘0’

Question 4 Explanation:
L= { λ, 0, 1λ, 01λ, 10, 010, 110, ………….}
According to the language L generated by given regular expression
Option(A) is incorrect because L contains 110.
Option(B) is correct because no string is containing 00
Option(C) is incorrect because not all strings in L are containing 01 example 0 in L does not contain 01.
Option(D) is incorrect because L contains 1λ is there in L which is not ending with 0.
Hence correct answer is option (B)
According to the language L generated by given regular expression
Option(A) is incorrect because L contains 110.
Option(B) is correct because no string is containing 00
Option(C) is incorrect because not all strings in L are containing 01 example 0 in L does not contain 01.
Option(D) is incorrect because L contains 1λ is there in L which is not ending with 0.
Hence correct answer is option (B)
Correct Answer: B
Question 4 Explanation:
L= { λ, 0, 1λ, 01λ, 10, 010, 110, ………….}
According to the language L generated by given regular expression
Option(A) is incorrect because L contains 110.
Option(B) is correct because no string is containing 00
Option(C) is incorrect because not all strings in L are containing 01 example 0 in L does not contain 01.
Option(D) is incorrect because L contains 1λ is there in L which is not ending with 0.
Hence correct answer is option (B)
According to the language L generated by given regular expression
Option(A) is incorrect because L contains 110.
Option(B) is correct because no string is containing 00
Option(C) is incorrect because not all strings in L are containing 01 example 0 in L does not contain 01.
Option(D) is incorrect because L contains 1λ is there in L which is not ending with 0.
Hence correct answer is option (B)
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