Programming
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Question 42
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The minimum number of arithmetic operations required to evaluate the polynomial P(X) = X5 + 4X3 + 6X + 5 for a given value of X, using only one temporary variable is ________.
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7
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8
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9
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10
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Question 42 Explanation:
The minimum number of arithmetic operations required to evaluate
P(X) = x5+4x3+6x+5
= x(x4+4x2+6)+5
= x(x(x3+4x)+6)+5
= x(x(x(x2+4))+6)+5
= x(x(x(x(x)+4))+6)+5
4 multiplications & 3 additions.
4 + 3 = 7
P(X) = x5+4x3+6x+5
= x(x4+4x2+6)+5
= x(x(x3+4x)+6)+5
= x(x(x(x2+4))+6)+5
= x(x(x(x(x)+4))+6)+5
4 multiplications & 3 additions.
4 + 3 = 7
Correct Answer: A
Question 42 Explanation:
The minimum number of arithmetic operations required to evaluate
P(X) = x5+4x3+6x+5
= x(x4+4x2+6)+5
= x(x(x3+4x)+6)+5
= x(x(x(x2+4))+6)+5
= x(x(x(x(x)+4))+6)+5
4 multiplications & 3 additions.
4 + 3 = 7
P(X) = x5+4x3+6x+5
= x(x4+4x2+6)+5
= x(x(x3+4x)+6)+5
= x(x(x(x2+4))+6)+5
= x(x(x(x(x)+4))+6)+5
4 multiplications & 3 additions.
4 + 3 = 7
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