C-Programming
October 18, 2023Boolean-Algebra
October 19, 2023Boolean-Algebra
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Question 1
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The Boolean function x’y’ + xy + x’y is equivalent to
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x’ + y’
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x + y
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x + y’
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x’ + y
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Question 1 Explanation:
x’y’ + xy + x’y
= x’y’ + x’y + xy
= x'(y’+y)+xy
= x’⋅1+xy
= x’+xy
= (x’+x)(x’+y)
= 1⋅(x’+y)
= x’+y
= x’y’ + x’y + xy
= x'(y’+y)+xy
= x’⋅1+xy
= x’+xy
= (x’+x)(x’+y)
= 1⋅(x’+y)
= x’+y
Correct Answer: D
Question 1 Explanation:
x’y’ + xy + x’y
= x’y’ + x’y + xy
= x'(y’+y)+xy
= x’⋅1+xy
= x’+xy
= (x’+x)(x’+y)
= 1⋅(x’+y)
= x’+y
= x’y’ + x’y + xy
= x'(y’+y)+xy
= x’⋅1+xy
= x’+xy
= (x’+x)(x’+y)
= 1⋅(x’+y)
= x’+y
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