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Question 7982 – Computer-Networks
November 21, 2023
Question 13888 – Software-Engineering
November 21, 2023
Question 7982 – Computer-Networks
November 21, 2023
Question 13888 – Software-Engineering
November 21, 2023

Question 11922 – Software-Engineering

Assume that the software team defines a project risk with 80% probability of occurrence of risk in the following manner :

Only 70 percent of the software components scheduled for reuse will be integrated into the application and the remaining functionality will have to be custom developed. If 60 reusable components were planned with average component size as 100 LOC and software engineering cost for each LOC as $ 14, then the risk exposure would be

Correct Answer: B

Question 395 Explanation: 
Risk Exposure(RE) = P × C
Where, P= Probability of occurrence of risk
C= Cost of risk
Only 70 percent of the software components scheduled for reuse will be integrated into the application .
It means 30% of total 60 reusable components have to be custom developed i.e. 60 ×(30/100) = 18.
18 components will be developed. Now Average component size is 100 LOC and cost of each LOC is $14.
So cost of risk = 18×100×14
= 25200
Risk Exposure(RE) = 0.8 ×25200
= 20160
A
$ 25,200
B
$ 20,160
C
$ 17,640
D
$ 15,120
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