Question 10642 – GATE 2008-IT
April 13, 2024UGC NET CS 2009-June-Paper-2
April 14, 2024Number-Systems
| Question 38 |
The addition of 4-bit, two’s complement, binary numbers 1101 and 0100 results in
| 0001 and an overflow | |
| 1001 and no overflow | |
| 0001 and no overflow | |
| 1001 and an overflow |
Question 38 Explanation:
2’s complement of 1101 = 0011
2’s complement of 1100 = 1100
Add = 1111
Now convert 1111 to normal form.
⇒ 0000 (1’s complement)
⇒ 0001 (2’s complement) No carry bit.
2’s complement of 1100 = 1100
Add = 1111
Now convert 1111 to normal form.
⇒ 0000 (1’s complement)
⇒ 0001 (2’s complement) No carry bit.
Correct Answer: C
Question 38 Explanation:
2’s complement of 1101 = 0011
2’s complement of 1100 = 1100
Add = 1111
Now convert 1111 to normal form.
⇒ 0000 (1’s complement)
⇒ 0001 (2’s complement) No carry bit.
2’s complement of 1100 = 1100
Add = 1111
Now convert 1111 to normal form.
⇒ 0000 (1’s complement)
⇒ 0001 (2’s complement) No carry bit.
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