Software-Engineering
August 28, 2024Software-Engineering
August 28, 2024Software-Engineering
| Question 373 |
The availability of complex software is 90% its Mean Time Between Failure(MTBF) is 200 days. Because of the critical nature of the usage, the organization deploying the software further enhanced it to obtain an availability of 95%. In the process, the Mean Time To Repair(MTTR) increased by 5 days. What is the MTBF of the enhanced software?(choose the nearest option)
| 205 days | |
| 300 days | |
| 500 days | |
| 700 days |
Question 373 Explanation:
Case-1:Availability of complex software =90% =0.9
Mean Time Between Failure(MTBF)=200
MTTR =?(we need to find )
Case-2:After enhancement modified ,availability= 95%=0.95,For this case,Mean Time To Repair(MTTR) increased by 5 days.
MTBF=?(we need to find )
Availability = MTBF/(MTBF + MTTR)
Case-1:
By substituting option-1 value, 0.9 = 200/(200 + MTTR) then
MTTR= 22.22
Case 2 :0.95 = MTBF/( MTBF+22.22+5)
MTBF= 517.18
Mean Time Between Failure(MTBF)=200
MTTR =?(we need to find )
Case-2:After enhancement modified ,availability= 95%=0.95,For this case,Mean Time To Repair(MTTR) increased by 5 days.
MTBF=?(we need to find )
Availability = MTBF/(MTBF + MTTR)
Case-1:
By substituting option-1 value, 0.9 = 200/(200 + MTTR) then
MTTR= 22.22
Case 2 :0.95 = MTBF/( MTBF+22.22+5)
MTBF= 517.18
Correct Answer: C
Question 373 Explanation:
Case-1:Availability of complex software =90% =0.9
Mean Time Between Failure(MTBF)=200
MTTR =?(we need to find )
Case-2:After enhancement modified ,availability= 95%=0.95,For this case,Mean Time To Repair(MTTR) increased by 5 days.
MTBF=?(we need to find )
Availability = MTBF/(MTBF + MTTR)
Case-1:
By substituting option-1 value, 0.9 = 200/(200 + MTTR) then
MTTR= 22.22
Case 2 :0.95 = MTBF/( MTBF+22.22+5)
MTBF= 517.18
Mean Time Between Failure(MTBF)=200
MTTR =?(we need to find )
Case-2:After enhancement modified ,availability= 95%=0.95,For this case,Mean Time To Repair(MTTR) increased by 5 days.
MTBF=?(we need to find )
Availability = MTBF/(MTBF + MTTR)
Case-1:
By substituting option-1 value, 0.9 = 200/(200 + MTTR) then
MTTR= 22.22
Case 2 :0.95 = MTBF/( MTBF+22.22+5)
MTBF= 517.18