NTA UGC NET Dec 2024 Paper-1
April 8, 2025
UGC NET CS 2006 Dec-paper-2
April 8, 2025
NTA UGC NET Dec 2024 Paper-1
April 8, 2025
UGC NET CS 2006 Dec-paper-2
April 8, 2025

UGC NET CS 2006 Dec-paper-2

Question 6
The hexadecimal equivalent of (10111)​ 2​ ×(1110)​ 2 is :
A
150
B
241
C
142
D
101011110
Question 6 Explanation: 
Step-1: First convert binary number into decimal number
(10111)​ 2​ = (23)​ 10
(1110)​ 2​ = (14)​ 10
Step-2: Perform multiplication 23*14=(322)​ 10
Step-3: Convert (322)​ 10​ into hexadecimal number
(322)​ 10​ = (142)​ 16
Correct Answer: C
Question 6 Explanation: 
Step-1: First convert binary number into decimal number
(10111)​ 2​ = (23)​ 10
(1110)​ 2​ = (14)​ 10
Step-2: Perform multiplication 23*14=(322)​ 10
Step-3: Convert (322)​ 10​ into hexadecimal number
(322)​ 10​ = (142)​ 16

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