Software-Engineering
November 18, 2023UGC-NET June CS 2019 Paper 1
November 19, 2023Software-Engineering
| Question 186 |
A signal processor software is expected to operate for 91.25 days after repair, and the mean software repair time is expected to be 5 minutes. Then, the availability of the software is:
| 96.9862% | |
| 97.9862% | |
| 98.9962% | |
| 99.9962% |
Question 186 Explanation:
Given data,
— Software expected to operate after repair(MTBF) = 91.25 days
= 91.25 * 24 hours
= 2190 hours
— Mean software repair time(MTTR) = 5 mins
= 5/60 hrs
= 0.083 hrs
— Software Availability=?
Step-1: Software Availability =MTBF / (MTBF + MTTR)
= [2190 / (2190 + 0.083)]*100
= (2190 / 2190.083)*100
= 0.9996211481 * 100
= 99.9962%
— Software expected to operate after repair(MTBF) = 91.25 days
= 91.25 * 24 hours
= 2190 hours
— Mean software repair time(MTTR) = 5 mins
= 5/60 hrs
= 0.083 hrs
— Software Availability=?
Step-1: Software Availability =MTBF / (MTBF + MTTR)
= [2190 / (2190 + 0.083)]*100
= (2190 / 2190.083)*100
= 0.9996211481 * 100
= 99.9962%
Correct Answer: D
Question 186 Explanation:
Given data,
— Software expected to operate after repair(MTBF) = 91.25 days
= 91.25 * 24 hours
= 2190 hours
— Mean software repair time(MTTR) = 5 mins
= 5/60 hrs
= 0.083 hrs
— Software Availability=?
Step-1: Software Availability =MTBF / (MTBF + MTTR)
= [2190 / (2190 + 0.083)]*100
= (2190 / 2190.083)*100
= 0.9996211481 * 100
= 99.9962%
— Software expected to operate after repair(MTBF) = 91.25 days
= 91.25 * 24 hours
= 2190 hours
— Mean software repair time(MTTR) = 5 mins
= 5/60 hrs
= 0.083 hrs
— Software Availability=?
Step-1: Software Availability =MTBF / (MTBF + MTTR)
= [2190 / (2190 + 0.083)]*100
= (2190 / 2190.083)*100
= 0.9996211481 * 100
= 99.9962%