Question 11430 – Operator

#include
int main()
{
int i=5;
printf("%d%d%d", i++, i ,++i);
return 0;
} 

int i=5;
printf(“%d%d%d”, i++, i ,++i);
In printf() the firstly the calculation is done from right to left and then printing is done from left to right.
So first ++i will increase the value of i by 1 and make it 6. Now the i will be read simply for second calculation.And now i++ will be calculated which will increment the value of i by 1 and make it 7, but since it is post increment so first 6 will be printed and then increment will be done and then for rest two 7 and 7 will be printed .Hence the output will be 6,7,7.