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November 21, 2023Software-Engineering
November 21, 2023Software-Engineering
| Question 119 |
Assume that the software team defines a project risk with 80% probability of occurrence of risk in the following manner :
Only 70 percent of the software components scheduled for reuse will be integrated into the application and the remaining functionality will have to be custom developed. If 60 reusable components were planned with average component size as 100 LOC and software engineering cost for each LOC as $ 14, then the risk exposure would be
| $ 25,200 | |
| $ 20,160 | |
| $ 17,640 | |
| $ 15,120 |
Question 119 Explanation:
Risk Exposure(RE) = P × C
Where, P= Probability of occurrence of risk
C= Cost of risk
Only 70 percent of the software components scheduled for reuse will be integrated into the application .
It means 30% of total 60 reusable components have to be custom developed i.e. 60 ×(30/100) = 18.
18 components will be developed. Now Average component size is 100 LOC and cost of each LOC is $14.
So cost of risk = 18×100×14
= 25200
Risk Exposure(RE) = 0.8 ×25200
= 20160
Where, P= Probability of occurrence of risk
C= Cost of risk
Only 70 percent of the software components scheduled for reuse will be integrated into the application .
It means 30% of total 60 reusable components have to be custom developed i.e. 60 ×(30/100) = 18.
18 components will be developed. Now Average component size is 100 LOC and cost of each LOC is $14.
So cost of risk = 18×100×14
= 25200
Risk Exposure(RE) = 0.8 ×25200
= 20160
Correct Answer: B
Question 119 Explanation:
Risk Exposure(RE) = P × C
Where, P= Probability of occurrence of risk
C= Cost of risk
Only 70 percent of the software components scheduled for reuse will be integrated into the application .
It means 30% of total 60 reusable components have to be custom developed i.e. 60 ×(30/100) = 18.
18 components will be developed. Now Average component size is 100 LOC and cost of each LOC is $14.
So cost of risk = 18×100×14
= 25200
Risk Exposure(RE) = 0.8 ×25200
= 20160
Where, P= Probability of occurrence of risk
C= Cost of risk
Only 70 percent of the software components scheduled for reuse will be integrated into the application .
It means 30% of total 60 reusable components have to be custom developed i.e. 60 ×(30/100) = 18.
18 components will be developed. Now Average component size is 100 LOC and cost of each LOC is $14.
So cost of risk = 18×100×14
= 25200
Risk Exposure(RE) = 0.8 ×25200
= 20160
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