Compiler-Design
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Question 48
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Consider the grammar shown below.
S → C C C → c C | d
The grammar is
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LL(1)
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SLR(1) but not LL(1)
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LALR(1) but not SLR(1)
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LR(1) but not LALR(1)
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Question 48 Explanation:
Hence, it is LL(1).
Correct Answer: A
Question 48 Explanation:
Hence, it is LL(1).
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