Parsers

Question 1
Which one of the following statements is TRUE?
A
The LALR (1) parser for a grammar G cannot have reduce-reduce conflict if the LR (1) parser for G does not have reduce-reduce conflict.
B
Symbol table is accessed only during the lexical analysis phase.
C
Data flow analysis is necessary for run-time memory management.
D
LR (1) parsing is sufficient for deterministic context-free languages.
Question 1 Explanation: 
Even though there is no reduce-reduce conflict in CLR(1) but in LALR(1) while merging the states differ in only lookahead may get reduce-reduce conflict. So the given statement is not true.
Symbol table is accessed in all the phases of compiler and not only in lexical analysis phase.
Data flow analysis is done in the control flow graph, in the code optimization phase. If LR(1) parses a grammar then definitely it is DCFL, so LR(1) parsing is sufficient for deterministic context-free languages.
Question 2
Consider the augmented grammar with { + , *, (, ), id } as the set of terminals.
A
5
Question 2 Explanation: 
Question 3
Consider the following grammar along with translation rules.
A
80
Question 3 Explanation: 
Question 4

Consider the following grammar.

     S → aSB|d
     B → b 

The number of reduction steps taken by a bottom-up parser while accepting the string aaadbbb is _______.

A
7
Question 4 Explanation: 

7 reductions total.
Question 5
Consider the following grammar:
stmt    →  if expr then expr else expr; stmt | ȯ
expr    →  term relop term | term
term    →  id | number
id      →  a | b |  c
number  → [0-9]
where relop is a relational operator (e.g., <, >, …), ȯ refers to the empty statement, and if, then, else are terminals.
Consider a program P following the above grammar containing ten if terminals. The number of control flow paths in P is ________. For example, the program
if e1 then e2 else e3 has 2 control flow paths, e1 → e2 and e1 → e3.

A
1024
B
1025
C
1026
D
1027
Question 5 Explanation: 
To get 10 'if' we need to use grammar to get,
if then else ; stmt
if then else ; if then else . stmt
:
:
:
(keep doing 10 times to get 10 'if')
We know that every if statement has 2 control flows as given in question. Hence,
We have 2 control flow choices for 1st 'if'
We have 2 control flow choices for 2nd 'if'
:
:
:
We have 2 control flow choices for 10th 'if'
Since all the choices are in one single structure or combination, so total choices are
2 × 2 × 2 × ........ 10 times = 210 = 1024
Question 6

Which of the following statements is true?

A
SLR parser is more powerful than LALR
B
LALR parser is more powerful than Canonical LR parser
C
Canonical LR parser is more powerful than LALR parser
D
The parsers SLR, Canonical CR, and LALR have the same power
Question 6 Explanation: 
LR > LALR > SLR
Canonical LR parser is more powerful than LALR parser.
Question 7

Which of the following is the most powerful parsing method?

A
LL (1)
B
Canonical LR
C
SLR
D
LALR
Question 7 Explanation: 
Canonical LR is most powerful.
LR > LALR > SLR
Question 8

Which of the following derivations does a top-down parser use while parsing an input string? The input is assumed to be scanned in left to right order.

A
Leftmost derivation
B
Leftmost derivation traced out in reverse
C
Rightmost derivation
D
Rightmost derivation traced out in reverse
Question 8 Explanation: 
Top-down parser - Leftmost derivation
Bottom-Up parser - Reverse of rightmost derivation
Question 9

Which of the following statements is false?

A
An unambiguous grammar has same leftmost and rightmost derivation
B
An LL(1) parser is a top-down parser
C
LALR is more powerful than SLR
D
An ambiguous grammar can never be LR(k) for any k
Question 9 Explanation: 
Option B: LL parser is a top-down parser for a subset of context-free languages. It parses the input from Left to right, performing Left most derivation of the sentence.
Option C: LALR is more powerful than SLR.
Option D: An ambiguous grammar can never be LR (k) for any k, because LR(k) algorithm aren’t designed to handle ambiguous grammars. It would get stuck into undecidability problem, if employed upon an ambiguous grammar, no matter how large the constant k is.
Question 10

Consider the following grammar with terminal alphabet ∑{a,(,),+,*} and start symbol E. The production rules of the grammar are:

              E → aA
              E → (E)
              A → +E
              A → *E
              A → ε 

(a) Compute the FIRST and FOLLOW sets for E and A.
(b) Complete the LL(1) parse table for the grammar.

A
Theory Explanation is given below.
Question 11

Assume that the SLR parser for a grammar G has n1 states and the LALR parser for G has n2 states. The relationship between n1 and n2 is:

A
n1 is necessarily less than n2
B
n1 is necessarily equal to n2
C
n1 is necessarily greater than n2
D
None of the above
Question 11 Explanation: 
No. of states in SLR and LALR are equal and no. of states in SLR and LALR are less than or equal to LR(1).
Question 12

Consider the grammar shown below

S → i E t S S' | a
S' → e S | ε
E → b 

In the predictive parse table. M, of this grammar, the entries M[S', e] and M[S', $] respectively are

A
{S'→e S} and {S'→ε}
B
{S'→e S} and { }
C
{S'→ε} and {S'→ε}
D
{S'→e S, S'→ε} and {S'→ε}
Question 12 Explanation: 
First(S) = {1,a}
First(S') = {e,ε}
First(E) = {b}
Follow(S') = {e,$}
Only when 'First' contains ε, we need to consider FOLLOW for getting the parse table entry.

Hence, option (D) is correct.
Question 13

Consider the grammar shown below.

S → C C
C → c C | d

The grammar is

A
LL(1)
B
SLR(1) but not LL(1)
C
LALR(1) but not SLR(1)
D
LR(1) but not LALR(1)
Question 13 Explanation: 

Hence, it is LL(1).
Question 14

Which of the following grammar rules violate the requirements of an operator grammar? P,Q,R are nonterminals, and r,s,t are terminals.

    (i) P → Q R
    (ii) P → Q s R
    (iii) P → ε
    (iv) P → Q t R r
A
(i) only
B
(i) and (iii) only
C
(ii) and (iii) only
D
(iii) and (iv) only
Question 14 Explanation: 
Operator values doesn't contains nullable values and two adjacent non-terminals on RHS production.
i) On RHS it contains two adjacent non-terminals.
ii) Have nullable values.
Question 15
Consider the SLR(1) and LALR (1) parsing tables for a context free grammar. Which of the following statements is/are true?
A
The go to part of both tables may be different.
B
The shift entries are identical in both tables.
C
The reduce entries in the tables may be different.
D
The error entries in the tables may be different.
Question 15 Explanation: 
Goto parts and shift entry must be same.
Reduce entry and error entry may be different due to conflicts.
Question 16
Consider the following augmented grammar with {#, @, <, >, a, B, c} as the set of terminals.
S’ ⟶ S
S ⟶ S#cS
S ⟶ SS
S ⟶ S@
S ⟶ < S >
S ⟶ a
S ⟶ b
S ⟶ c  
Let I0=CLOSURE({S' ⟶.S}). The number of items in the set GOTO(GOTO(I0, <), <) is ____________.
A
8
Question 16 Explanation: 
Question 17

An operator precedence parser is a

A
Bottom-up parser.
B
Top-down parser.
C
Back tracking parser.
D
None of the above.
Question 17 Explanation: 
An operator precedence parser is a Bottom-up parser.
Question 18

Merging states with a common core may produce __________ conflicts and does not produce ___________ conflicts in an LALR purser.

A
Reduce-Reduce, Shift-Reduce
Question 18 Explanation: 
Merge states with a common core may produce Reduce-Reduce conflicts and does not produce Shift-Reduce conflicts in an LALR parser.
Question 19

Choose the correct alternatives (more than one may be correct) and write the corresponding letters only: Indicate all the true statements from the following:

A
Recursive descent parsing cannot be used for grammar with left recursion.
B
The intermediate form the representing expressions which is best suited for code optimization is the post fix form.
C
A programming language not supporting either recursion or pointer type does not need the support of dynamic memory allocation.
D
Although C does not support call by name parameter passing, the effect can be correctly simulated in C.
E
No feature of Pascal violates strong typing in Pascal.
F
A and D
Question 19 Explanation: 
(A) It is true. Left recursive grammar if used directly in recursive descent parsing causes an infinite loop. So, left recursion must be removed before giving to a recursive descent parser.
(B) False.
(C) It is false. The language can have dynamic data types which required dynamically growing memory when data type size increases.
(D) Is true and using macro we can do this.
(E) Out of syllabus now.
Question 20

The grammar A → AA | (A) | ε is not suitable for predictive-parsing because the grammar is:

A
ambiguous
B
left-recursive
C
right-recursive
D
an operator-grammar
Question 20 Explanation: 
The given grammar can be turned into a infinite parse tree. So it is ambiguous.
It have A → AA has left recursion.
Question 21

Consider the grammar:

   S → (S) | a 

Let the number of states in SLR(1), LR(1) and LALR(1) parsers for the grammar be n1, n2 and n3 respectively. The following relationship holds good:

A
n1 < n2 < n3
B
n1 = n3 < n2
C
n1 = n2 = n3
D
n1 ≥ n3 ≥ n2
Question 21 Explanation: 
→ SLR(1) and LALR(1) both are be the states of LR(0) items then SLR(1) = LALR(1).
→ LR(1) be the states of LR(1) items.
→ LR(0) items never be greater than LR(1) items then SLR(1) = LALR(1) < LR(1)
n1 = (n3) < (n2)
Question 22

Consider the following expression grammar. The seman­tic rules for expression calculation are stated next to each grammar production.

E → number 	 E.val = number. val
    |E '+' E 	 E(1).val = E(2).val + E>sup>(3).val
    |E '×' E	 E(1).val = E(2).val × E(3).val

The above grammar and the semantic rules are fed to a yacc tool (which is an LALR(1) parser generator) for parsing and evaluating arithmetic expressions. Which one of the following is true about the action of yacc for the given grammar?

A
It detects recursion and eliminates recursion
B
It detects reduce-reduce conflict, and resolves
C
It detects shift-reduce conflict, and resolves the conflict in favor of a shift over a reduce action
D
It detects shift-reduce conflict, and resolves the conflict in favor of a reduce over a shift action
Question 22 Explanation: 
Yacc favours shift move in case of SR conflict.
Question 23

Consider the following expression grammar. The seman­tic rules for expression calculation are stated next to each grammar production.

E → number 	 E.val = number. val
    |E '+' E 	 E(1).val = E(2).val + E>sup>(3).val
    |E '×' E	 E(1).val = E(2).val × E(3).val

Assume the conflicts in Part (a) of this question are resolved and an LALR(1) parser is generated for parsing arithmetic expressions as per the given grammar. Consider an expression 3 × 2 + 1. What precedence and associativity properties does the generated parser realize?

A
Equal precedence and left associativity; expression is evaluated to 7
B
Equal precedence and right associativity; expression is evaluated to 9
C
Precedence of '×' is higher than that of '+', and both operators are left associative; expression is evaluated to 7
D
Precedence of '+' is higher than that of '×', and both operators are left associative; expression is evaluated to 9
Question 23 Explanation: 
First of all, it is ambiguous grammar. Hence, equal precedence and associativity. Now as Yacc resolved it with shift move we will shift until the last operator and then we will start reducing.

Hence, the answer is 9 and right associative.
Question 24

Consider the following grammar.

   S → S * E
   S → E
   E → F + E
   E → F
   F → id 

Consider the following LR(0) items corresponding to the grammar above.

(i) S → S * .E
(ii) E → F. + E
(iii) E → F + .E 

Given the items above, which two of them will appear in the same set in the canonical sets-of-items for the grammar?

A
(i) and (ii)
B
(ii) and (iii)
C
(i) and (iii)
D
None of the above
Question 24 Explanation: 
As we can see in the below given LR(0) items, that all three belongs to different state (sets).
Question 25

Consider the following grammar:

   S → FR
   R → S | ε
   F → id

In the predictive parser table, M, of the grammar the entries M[S,id] and M[R,$] respectively.

A
{S → FR} and {R → ε}
B
{S → FR} and { }
C
{S → FR} and {R → *S}
D
{F → id} and {R → ε}
Question 25 Explanation: 
Predictive parsing table for the mentioned grammar:

The representation M[X,Y] means X represents Variable (rows) and Y represents terminals (columns).
The productions are filled in parsing table by the below mentioned rules:
For every production P → α, we have:
Rule 1: If P → α is a production then add this production for each terminal “t” which is in FIRST of [α] i.e., ADD P → α to M[P, a]
Rule 2: If “ϵ” belongs to FIRST of [P] then add P → α to M[P, b] where “b” represents terminals FOLLOW[P].
By the above rules, we can see that production S → FR will go M[S, a] where “a” is FIRST [FR] which is equal to FIRST[F] = id, So S → FR will go in M[S,id].
Since in the production R→ϵ , FIRST[ϵ] = ϵ, hence the production will go in M[R, b] where “b” represents terminals FOLLOW[R] and FOLLOW[R] = $, so production R→ϵ will go in M[R,$]
Question 26

Which one of the following is a top-down parser?

A
Recursive descent parser.
B
Operator precedence parser.
C
An LR(k) parser.
D
An LALR(k) parser.
Question 26 Explanation: 
Recursive descent parser is top down parser, while others are bottom up parser.
Question 27

Consider the grammar with non-terminals N = {S,C,S1},terminals T = {a,b,i,t,e}, with S as the start symbol, and the following set of rules:

      S --> iCtSS1|a
      S1 --> eS|ϵ
      C --> b

The grammar is NOT LL(1) because:

A
it is left recursive
B
it is right recursive
C
it is ambiguous
D
it is not context-free
Question 27 Explanation: 
The given grammar is not left recursive and also it is context free (Type 2 grammar), so option A and D is wrong. Being a right recursive grammar is not an issue for LL(1) grammar. So even if given grammar is right recursive, this is not a reason for NOT LL(1).
This grammar has two parse tree for string “ibt ibt aea”.
Question 28

Consider the following two statements:

P: Every regular grammar is LL(1)
Q: Every regular set has a LR(1) grammar

Which of the following is TRUE?

A
Both P and Q are true
B
P is true and Q is false
C
P is false and Q is true
D
Both P and Q are false
Question 28 Explanation: 
Every regular grammar is LL(1) is false, as the grammar may have left recursion or left factoring or also it is possible that grammar is ambiguous.
For ex: Consider a regular grammar
S -> aS | a | ϵ
this grammar is ambiguous as for string "a" two parse tree is possible.

Hence it is regular but not LL(1).
But every regular set has a language accept or as DFA , so every regular set must have atleast one grammar which is unambiguous.
Hence, every regular set has LR(1) grammar.
Question 29

Among simple LR (SLR), canonical LR, and look-ahead LR (LALR), which of the following pairs identify the method that is very easy to implement and the method that is the most powerful, in that order?

A
SLR, LALR
B
Canonical LR, LALR
C
SLR, canonical LR
D
LALR, canonical LR
Question 29 Explanation: 
SLR is very easy to implement and CLR is most powerful method.
Question 30

Consider the following grammar G.

  S → F ⎪ H
  F → p ⎪ c
  H → d ⎪ c

Where S, F and H are non-terminal symbols, p, d and c are terminal symbols. Which of the following statement(s) is/are correct?

    S1: LL(1) can parse all strings that are generated using grammar G.
    S2: LR(1) can parse all strings that are generated using grammar
A
Only S1
B
Only S2
C
Both S1 and S2
D
Neither S1 nor S2
Question 30 Explanation: 
For LL(1),
For first production,

So, there is 'c' common in both the first(s) in the production of S. So not LL(1).
For LR(1),

Since R-R conflict is present. So, not LR(1).
Hence, Option (D) is the correct answer.
Question 31

A shift reduce parser carries out the actions specified within braces immediately after reducing with the corresponding rule of grammar

S → xxW {print "1"}
S → y {print "2"}
W → Sz {print "3"} 

What is the translation of xxxxyzz using the syntax directed translation scheme described by the above rules?

A
23131
B
11233
C
11231
D
33211
Question 31 Explanation: 

⇒ 23131
Note SR is bottom up parser.
There are 31 questions to complete.

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