Rate of interest=((11248.64 - 10816)/10816) * 100
= (432.64 / 10816)*100
= 4%

'AEIOU' is written as 'TNHDZ'
The above code following 2 conditions
1. character-1
2. Firs position is replaced with last position
A-1= Z and placed in last
E-1= D placed in second last
I-1=H placed in third last
O-1=N placed in fourth last
S-1=T placed in first position

The same order will follow for 'BFJPV'
B-1= A placed in last
F-1=E is placed in second last
J-1=I is placed in third last
P-1=O is placed in fourth last
V-1=U is placed in first position.

Single equivalent discount for successive discounts of 10% and 15%.
= (10+15- (15*10)/100)%
= 23.5%
Single equivalent discount for 23.5% and 20%
=(23.5+20-(23.5*20)/100)%
=38.8%

Given : a + 1/a = - 4
Find: a^3 + (1/a)^3
Solution: a + 1/a = -4
Take cube on both sides
(a + 1/a)^3 = (-4)^3
a^3 + (1/a)^3 + 3*a* 1/a (a+1/a) = -64
a^3 + (1/a)^3 + 3(a+1/a) = -64
a^3 + (1/a)^3 - 12 = -64
a^3 + (1/a)^3 = - 64 + 12
a^3 + (1/a)^3 = -52

When A completes 100m, B is at 90m which is 10m behind.Now A beats B by 2 secs.
This means B takes 2 more seconds to complete the race
As B is 10m behind when A completes the race, so B takes 2 secs to complete 10m
Speed of B = 5m/s
Total time of B = 100/5 = 20 secs
Time of A = 20 - 2 = 18 seconds
Speed of A = 100/18 = 5.555

Ration of ages of three persons= A:B:C= 3:4:5
Average of three is 40 years
What is the B’s age=?
We can’t get more than 120 as their age because the average of 3 persons is 40.
B is elder than A and younger than C
= 20+40+60
= 120
Average = (120/3)=40

Three pipes fill a tank in 4 hours
P1 takes 8 hours and in one hour work is 1/8
P2 takes 12 hours and and in one hour work is 1/12
P3 takes x hours and and in one hour work is 1/x
Amount of work done by both p1 and p2=(⅛+1/12+1/x)=5/24+1/x
Now 1/x=1/4-5/24=6-5/24=1/24
P3 will take 24 hours to fill the tank

Input’s:
C is the brother of D’s husband and son of A
F is the daughter of D
F is sister of E
B=? [ Hint: D’s Husband ]

2² = 4
3³ = 27
4⁴ = 256
5⁵ = 3125
6⁶ = 46656

5%P = (15/100)*Q
(10/100)*Q = (20/100)*R
(20/100)*2000
=4000
(10/100)*Q = 4000
Q = 4000

(5/100)*P = (15/100)*4000
=600
P = (600*100)/5
P=12000

If P has a daughter Q, then Q related to Z is Aunt.

Y related to O is wife.

O related to Z is father.

P related to X is Grandmother.

Ram can do a piece of work = 5 days
Sham can do a piece of work = 10 days
Ram + Sham + Karan = 2 days
Karan= 5 days

₹ 1000 invested in compound interest becomes ₹ 2000 in 10 years.
The amount will double again in another 10 years.
The amount will become ₹ 2000 in another 10 years.
So, to earn another ₹ 2000 interest, it will take another 10 years.

‘34’ is wrong number in place of 34, the number ‘36’ is correct sequence.

PAN = 31 → (1)
PAR = 35 → (2)
PAT = 37
From (1) & (2), PA = 3; Difference between N to R is (5 - 1) = 4 i.e., no. of alphabets between N & R such as no. of alphabets between R and T is ‘2’ then ‘7’ is correct number. Difference between 7 and 5 is 2.

5 + 4 + 7 + 2 = 18 = (1 + 8) = 9; 6 + 3 + 4 + 2 = 15 = (1 + 5) = 6
7 + 5 + 8 + 4 = 24 = (2 + 4) = 6; 9 + 2 + 3 + 6 = 20 = (2 + 0) = 2

River ganga doesn’t pass through LUCKNOW.

Given data:
Total number of students = 210
1/3 rd of 210 = 70 students
Mean marks of 70 students = 60
To Find: Mean of the whole group= ?
Let the sum of marks of 70 students be X
Mean = X / Number of students
60 = X/70
X = 70*60

⇒ Sum of marks of 70 students = 4200
Remaining students = 210 - 70 = 140 students
Mean of 140 students = 78
Sum of marks of 78 students = 140*78 = 10920
Total marks of 210 students = 4200 + 10920
= 15120
Mean of whole group = 15120 / 210
= 72 marks