COCOMO-Model
Question 1 |
Consider the basic COCOMO model where E is the effort applied in person-months, D is the development time in chronological months, KLOC is the estimated number of delivered lines of code (in thousands) and ab, bb, cb, db have their usual meanings. The basic COCOMO equations are of the form
E = a b(KLOC)exp (b b, D = c b(E)exp (d b) | |
E = a b(KLOC)exp (b b, D = c b(E)exp (d b) | |
E = a bexp(b b), D = c b(KLOC)exp (d b) | |
E = a bexp(D b), D = c b(KLOC)exp (b b) |
Effort applied (E) = ab(KLOC)bb
Development time (D) = cb(E)db
Question 2 |
A company needs to develop digital signal processing software for one of its newest inventions. The software is expected to have 40000 lines of code. The company needs to determine the effort in person-months needed to develop this software using the basic COCOMO model. The multiplicative factor for this model is given as 2.8 for the software development on embedded systems, while the exponentiation factor is given as 1.20. What is the estimated effort in person-months?
234.25 | |
932.50 | |
287.80 | |
122.40 |
Question 3 |
10.52 months | |
11.52 months | |
12.52 months | |
14.52 months |
-- lines of code(LOC)= 20,000 (or 20K)
-- Multiplicative value ‘a’=2.4
-- Exponential ‘b’=1.05
-- Basic COCOMO formula= a*(LOC in K)b
-- Multiplicative value ‘c’=2.5
-- Exponential ‘d’=0.38
-- Development=c*(basic COCOMO result)d
Step-1: Basic COCOMO formula= a*(LOC in K)b
= 2.4*(20)1.05
= 55.756
Step-2: Development= c*(basic COCOMO result)d
= 2.5(55.756)0.38
= 11.52 months
Question 4 |
embedded | |
semidetached | |
detached | |
organic |