NAND and NOR operation follow commutativity but do not follow associativity.

NOR gate, NAND gate, Multiplexers and Half adders can also be used to realize all digital circuits.

3+1+5∗2 / 7+2−4−7−6 / 2  ⇒ [ 3+1] +5∗2 / 7+2−4−7−6 / 2      [ + is highest precedence and its associativity is left ] => [4+5]∗2 / 7+2−4−7−6 / 2 [ + is highest precedence and its associativity is left ] => 9*2  / [7+2]−4−7−6 / 2 [ + is highest precedence and its associativity is left ] => 9*2  / 9 −4−7−6 / 2 => 9*2  / 9 −4−[7−6] / 2 [ - is high precedence and its associativity is Right ] => 9*2  / 9 −[4−1] / 2 [ - is high precedence and its associativity is Right ] => 9*2  / [9 −3] / 2 [ - is high precedence and its associativity is Right ] => 9*2  / 6 / 2 [ *  is next  precedence and its associativity is Right ] => 18/6/2 =>18/[6/2] [ only / operator and  its associativity is Right ] => 18 / 3 => 6

→In the option B, -10%-2 gives remainder of “0” and then expression becomes 4/0/3.
→4/0 gives divide by zero error.

Bitwise AND is a binary operator that operates on two equal-length bit patterns. If both bits in the compared position of the bit patterns are 1, the bit in the resulting bit pattern is 1, otherwise 0.
Bitwise OR is also a binary operator that operates on two equal-length bit patterns, similar to bitwise AND. If both bits in the compared position of the bit patterns are 0, the bit in the resulting bit pattern is 0, otherwise 1.
Bitwise XOR also takes two equal-length bit patterns. If both bits in the compared position of the bit patterns are 0 or 1, the bit in the resulting bit pattern is 0, otherwise 1.

‘*’ and ‘%’ operator have the same precedence but the associativity is from left to write. So x = 3*4%5 = 12%5 = 2.

In C++ operator, << operator is called as an an insertion operator or put to operator.

In XOR,
1 XOR 1 = 0
1 XOR 0 =1
0 XOR 0 = 0
0 XOR 1 = 1
So 5 in binary form is 00000101 and 2 in binary form is 00000010.
Hence 00000101 XOR 00000010 = 00000111.

int i=5;
printf("%d%d%d", i++, i ,++i);
In printf() the firstly the calculation is done from right to left and then printing is done from left to right.
So first ++i will increase the value of i by 1 and make it 6. Now the i will be read simply for second calculation.And now i++ will be calculated which will increment the value of i by 1 and make it 7, but since it is post increment so first 6 will be printed and then increment will be done and then for rest two 7 and 7 will be printed .Hence the output will be 6,7,7.

In general, a-=b means a=a-b. So from this we can conclude that correct option is A.