UGC NET CS 2009 Dec-Paper-2
October 10, 2023UGC NET CS 2009 Dec-Paper-2
October 10, 2023UGC NET CS 2009 Dec-Paper-2
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Question 10
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How many 1’s are present in the binary representation of 3 × 512 + 7 × 64 + 5 × 8 + 3
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8
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9
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10
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11
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Question 10 Explanation:
Given expression is 3 × 512 + 7 × 64 + 5 × 8 + 3
We can write above statement based on precedence is (3 * 512) + (7 * 64) + (5 * 8) + 3
Step-1: 1536+448+40+3
Step-2: (2027)10
Step-3: Equivalent binary number is (011111101011)2
Note: Total number of 1’s is 9.
We can write above statement based on precedence is (3 * 512) + (7 * 64) + (5 * 8) + 3
Step-1: 1536+448+40+3
Step-2: (2027)10
Step-3: Equivalent binary number is (011111101011)2
Note: Total number of 1’s is 9.
Correct Answer: B
Question 10 Explanation:
Given expression is 3 × 512 + 7 × 64 + 5 × 8 + 3
We can write above statement based on precedence is (3 * 512) + (7 * 64) + (5 * 8) + 3
Step-1: 1536+448+40+3
Step-2: (2027)10
Step-3: Equivalent binary number is (011111101011)2
Note: Total number of 1’s is 9.
We can write above statement based on precedence is (3 * 512) + (7 * 64) + (5 * 8) + 3
Step-1: 1536+448+40+3
Step-2: (2027)10
Step-3: Equivalent binary number is (011111101011)2
Note: Total number of 1’s is 9.