UGC NET CS 2010 Dec-Paper-2
October 11, 2023UGC NET CS 2010 Dec-Paper-2
October 11, 2023Digital-Logic-Design
| Question 601 |
Encoding of data bits 0011 into 7-bit even Parity Hamming Code is
| 0011110 | |
| 0101110 | |
| 0010110 | |
| 0011100 |
Question 601 Explanation:
(m) Data = 0011
No. of parity bits needed is decided using
2p≥ m+p+1
p=3
Bit pattern:
P1(check even parity at 1, 3, 5, 7 bit) = 0
P2(check even parity at 2, 3, 6, 7 bit) = 1
P4(check even parity at 4, 5, 6, 7 bit) = 1
So encoded data = 0011110
No. of parity bits needed is decided using
2p≥ m+p+1
p=3
Bit pattern:
P1(check even parity at 1, 3, 5, 7 bit) = 0
P2(check even parity at 2, 3, 6, 7 bit) = 1
P4(check even parity at 4, 5, 6, 7 bit) = 1
So encoded data = 0011110
Correct Answer: A
Question 601 Explanation:
(m) Data = 0011
No. of parity bits needed is decided using
2p≥ m+p+1
p=3
Bit pattern:
P1(check even parity at 1, 3, 5, 7 bit) = 0
P2(check even parity at 2, 3, 6, 7 bit) = 1
P4(check even parity at 4, 5, 6, 7 bit) = 1
So encoded data = 0011110
No. of parity bits needed is decided using
2p≥ m+p+1
p=3
Bit pattern:
P1(check even parity at 1, 3, 5, 7 bit) = 0
P2(check even parity at 2, 3, 6, 7 bit) = 1
P4(check even parity at 4, 5, 6, 7 bit) = 1
So encoded data = 0011110
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