UGC NET CS 2007 June-Paper-2
October 13, 2023UGC NET CS 2007 June-Paper-2
October 13, 2023UGC NET CS 2007 June-Paper-2
| Question 8 |
How many 1’s are present in the binary representation of 15*256 + 5*16 + 3 :
| 8 | |
| 9 | |
| 10 | |
| 11 |
Question 8 Explanation:
Step-1: The precedence to given decimal number is (15*256) + (5*16) + 3
Step-2: 3840+80+3=(3923)10
Step-3: Convert decimal number into binary
(3923)10 = (111101010011 )2
Step-4: Total number of 1’s are 8.
Step-2: 3840+80+3=(3923)10
Step-3: Convert decimal number into binary
(3923)10 = (111101010011 )2
Step-4: Total number of 1’s are 8.
Correct Answer: A
Question 8 Explanation:
Step-1: The precedence to given decimal number is (15*256) + (5*16) + 3
Step-2: 3840+80+3=(3923)10
Step-3: Convert decimal number into binary
(3923)10 = (111101010011 )2
Step-4: Total number of 1’s are 8.
Step-2: 3840+80+3=(3923)10
Step-3: Convert decimal number into binary
(3923)10 = (111101010011 )2
Step-4: Total number of 1’s are 8.
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