GATE 2023
October 15, 2023Data-Structures
October 16, 2023Digital-Logic-Design
Question 392
|
Let M = 11111010 and N = 00001010 be two 8 bit two’s complement number. Their product in two’s complement is
11000100
|
|
10011100
|
|
10100101
|
|
11010101
|
Question 392 Explanation:
A = 1111 1010 = -610 [2’s complement number]
B = 0000 1010 = 1010 [2’s complement number]
A×B = -6×10 = – 6010
⇒ -6010 = 101111002
= 110000112 (1’s complement)
= 110001002 (2’s complement)
B = 0000 1010 = 1010 [2’s complement number]
A×B = -6×10 = – 6010
⇒ -6010 = 101111002
= 110000112 (1’s complement)
= 110001002 (2’s complement)
Correct Answer: A
Question 392 Explanation:
A = 1111 1010 = -610 [2’s complement number]
B = 0000 1010 = 1010 [2’s complement number]
A×B = -6×10 = – 6010
⇒ -6010 = 101111002
= 110000112 (1’s complement)
= 110001002 (2’s complement)
B = 0000 1010 = 1010 [2’s complement number]
A×B = -6×10 = – 6010
⇒ -6010 = 101111002
= 110000112 (1’s complement)
= 110001002 (2’s complement)
Subscribe
Login
0 Comments