SoftwareEngineering
November 20, 2023Question 17162 – NTA UGC NET JUNE2023 Paper2
November 20, 2023COCOMOModel
Question 3

A simple stand – alone software utility is to be developed in ‘C’ programming by a team of software experts for a computer running Linux and the overall size of this software is estimated to be 20,000 lines of code. Considering (a, b) = (2.4, 1.05) as multiplicative and exponention factor for the basic COCOMO effort estimation equation and (c, d) = (2.5, 0.38) as multiplicative and exponention factor for the basic COCOMO development time estimation equation, approximately how long does the software project take to complete ?
10.52 months


11.52 months


12.52 months


14.52 months

Question 3 Explanation:
Given data,
— lines of code(LOC)= 20,000 (or 20K)
— Multiplicative value ‘a’=2.4
— Exponential ‘b’=1.05
— Basic COCOMO formula= a*(LOC in K)^{b}
— Multiplicative value ‘c’=2.5
— Exponential ‘d’=0.38
— Development=c*(basic COCOMO result)^{d}
Step1: Basic COCOMO formula= a*(LOC in K)^{b}
= 2.4*(20)^{1.05}
= 55.756
Step2: Development= c*(basic COCOMO result)^{d}
= 2.5(55.756)^{0.38}
= 11.52 months
— lines of code(LOC)= 20,000 (or 20K)
— Multiplicative value ‘a’=2.4
— Exponential ‘b’=1.05
— Basic COCOMO formula= a*(LOC in K)^{b}
— Multiplicative value ‘c’=2.5
— Exponential ‘d’=0.38
— Development=c*(basic COCOMO result)^{d}
Step1: Basic COCOMO formula= a*(LOC in K)^{b}
= 2.4*(20)^{1.05}
= 55.756
Step2: Development= c*(basic COCOMO result)^{d}
= 2.5(55.756)^{0.38}
= 11.52 months
Correct Answer: B
Question 3 Explanation:
Given data,
— lines of code(LOC)= 20,000 (or 20K)
— Multiplicative value ‘a’=2.4
— Exponential ‘b’=1.05
— Basic COCOMO formula= a*(LOC in K)^{b}
— Multiplicative value ‘c’=2.5
— Exponential ‘d’=0.38
— Development=c*(basic COCOMO result)^{d}
Step1: Basic COCOMO formula= a*(LOC in K)^{b}
= 2.4*(20)^{1.05}
= 55.756
Step2: Development= c*(basic COCOMO result)^{d}
= 2.5(55.756)^{0.38}
= 11.52 months
— lines of code(LOC)= 20,000 (or 20K)
— Multiplicative value ‘a’=2.4
— Exponential ‘b’=1.05
— Basic COCOMO formula= a*(LOC in K)^{b}
— Multiplicative value ‘c’=2.5
— Exponential ‘d’=0.38
— Development=c*(basic COCOMO result)^{d}
Step1: Basic COCOMO formula= a*(LOC in K)^{b}
= 2.4*(20)^{1.05}
= 55.756
Step2: Development= c*(basic COCOMO result)^{d}
= 2.5(55.756)^{0.38}
= 11.52 months
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